Question

我有两个csv列，我需要比较这两列并将结果写在第三列（结果）。

“线”， “路径”， “结果”

“RETENTION_LEVEL 3 1 1 1 1 1 1 1 1 1”，“C：\ Veritas \ NetBackup \ db \ class \ policy-v- \ schedule \ cum \ info”，

如何使第三列的变量可设置？

#Write retention and policy in a csv file. 
$file="C:\Users\toto\schedules.csv"
#Write analysis results in a final csv.
$finalFile="C:\Users\toto\bad_retention.csv"
#query to find information based on the retention level and policy + export in the csv
$find=Get-ChildItem "C:\Veritas\NetBackup\db\class\" -recurse | Select-String -pattern "RETENTION_LEVEL" | Select line,path,@{Expression={$_.result};Label="Result";} | Export-CSV $file –NoTypeInformation

        (Import-Csv $file -Delimiter ',')

        ForEach-Object{
            if(($_.line -match "RETENTION_LEVEL 1 1 1 1 1 1 1 1 1 1") -and ($_.path -match "-v-"))
            {
             $_.result="BAD RETENTION"
             echo $_result;
            }
            else
            {
             $_.result="OK";
             echo $_result;
            }
        } | Export-CSV $finalFile –NoTypeInformation

Property 'result' cannot be found on this object; make sure it exists and is settable.
At C:\Users\toto\Documents\bad_retention.ps1:28 char:17
+              $_. <<<< result="OK";
    + CategoryInfo          : InvalidOperation: (result:String) [], RuntimeException
    + FullyQualifiedErrorId : PropertyNotFound

Answer 1

未经测试：

Get-ChildItem "C:\Veritas\NetBackup\db\class\" -recurse |
 Select-String -pattern "RETENTION_LEVEL" |
 Select line,path,@{
  Label = 'result'
  Expression = {('OK','BAD RETENTION')[($_.line -match "RETENTION_LEVEL 1 1 1 1 1 1 1 1 1 1") -and ($_.path -match "-v-")]}
  } |
  Export-CSV $file –NoTypeInformation

Answer 2

使用下面的语法，它可以“：

Expression = {('OK','BAD RETENTION')[($_.line -eq "RETENTION_LEVEL 1 1 1 1 1 1 1 1 1 1")]}

Powershell - 比较两个csv行并在第三个中写入结果

2 个答案: