Question

我试图向屏幕显示超链接，但前提是相应的ID记录在字符串中。

<?php
function check($i, $s) {
    if (preg_match('/'.$i.'/',$test)) echo $s;
}

$test = "000,001,002,003,004,005";

check("001","<a href=''>This is in the test string - 001</a>");
check("003","<a href=''>This is in the test string - 003</a>");
check("006","<a href=''>This is in the test string - 006</a>");
check("020","<a href=''>This is in the test string - 020</a>");
?>

所需的输出是：

<a href=''>This is in the test string - 001</a>
<a href=''>This is in the test string - 003</a>

因为它们是字符串中值的唯一两个匹配项。

这不起作用..你能告诉为什么以及如何让它发挥作用。？

由于

Answer 1

您尚未在函数中定义变量$ test。你可以做，例如，

<?php
function check($i, $s, $test) {
    if (preg_match('/'.$i.'/',$test)) echo $s;
}

$test = "000,001,002,003,004,005";

check("001","<a href=''>This is in the test string - 001</a>", $test);
check("003","<a href=''>This is in the test string - 003</a>", $test);
check("006","<a href=''>This is in the test string - 006</a>", $test);
check("020","<a href=''>This is in the test string - 020</a>", $test);
?>

开发时应使用error_reporting(E_ALL);，在这种情况下，您会看到以下消息：

Notice: Undefined variable: test in ... on line ...

PHP preg_match - 如果匹配则回显结果？

1 个答案: