Question

我有一个表叫学生。我想要一个学生的名字，其中isactive是1，并且有主题代码1.Like在这里不起作用。它给出了主题代码为11或12的员工的姓名。

id  name    Isactive    subjectcode
1   Shilpa  1           1,2,3
2   Manasi  1           11
3   kamal   1           12,3
4   Hans    0           1,2
5   Rupali  1          1,11,12

Answer 1

首先创建此功能

create function [dbo].[fnSplitString]
(
    @string nvarchar(max)
    ,@delimiter char(1) = ','
)
returns @t table(string nvarchar(max))
as 
begin 
    declare @pos int
    declare @piece varchar(500)

    if right(rtrim(@string),1) <> @delimiter
     set @string = @string  + @delimiter

    set @pos =  patindex('%' + @delimiter + '%' , @string)
    while @pos <> 0 
    begin
     set @piece = left(@string, @pos - 1)

    insert  @t
    select  @piece

     set @string = stuff(@string, 1, @pos,'')
     set @pos =  patindex('%' + @delimiter + '%' , @string)
    end 
    return
end

然后运行

DECLARE @result TABLE (id Int,name Varchar(50),isactive Bit, subjectCode Varchar(200))

INSERT INTO @result 
SELECT 1 ,  'Shilpa' , 1    ,       '1,2,3'
INSERT INTO @result 
SELECT 2 , 'Manasi' , 1    ,       '11'
INSERT INTO @result 
SELECT 3 ,  'kamal',   1    ,       '12,3'
INSERT INTO @result 
SELECT 4 ,  'Hans' ,   0     ,      '1,2'
INSERT INTO @result 
SELECT 5 ,  'Rupali' , 1    ,      '1,11,12'

    SELECT * FROM @result WHERE isactive=1 AND 
(11 IN(SELECT * FROM [dbo].[fnSplitString](subjectCode,',')) 
OR 12 in
(SELECT * FROM [dbo].[fnSplitString](subjectCode,',')))

Answer 2

你可以尝试下面的SQL查询

DECLARE @result TABLE (id Int,name Varchar(50),isactive Bit, subjectCode Varchar(200))

INSERT INTO @result 
SELECT 1 ,  'Shilpa' , 1    ,       '1,2,3'
INSERT INTO @result 
SELECT 2 , 'Manasi' , 1    ,       '11'
INSERT INTO @result 
SELECT 3 ,  'kamal',   1    ,       '12,3'
INSERT INTO @result 
SELECT 4 ,  'Hans' ,   0     ,      '1,2'
INSERT INTO @result 
SELECT 5 ,  'Rupali' , 1    ,      '1,11,12'

select * from @result where Isactive = 1 and (','+ subjectcode + ',') like '%,' + '1' + ',%'

Answer 3

请使用以下条件而不是像

where CHARINDEX('1,',subjectcode) > 0 or CHARINDEX(',1',subjectcode) > 0

这样可行。

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