类无法存储

Question

我一直在开发BPMN编辑器，可以根据上下文菜单修改任务。我使用this来实现它。

因此，每当用户更改任务类型时，都会调用一个类。但是我很难想出来拯救这门课程。因为每当用户更改所选项目时，“当前”项目将会更改，并且将删除之前的类别。我保存了类名但我无法检索。我现在卡住了。谢谢你的帮助。

这是我到目前为止所尝试的：

menu_shape= function(){
    $.contextMenu({
        selector: '.activity',
        trigger: 'left',
        callback: function(key, options) {
            var m = key;
            menu_shape_action(key);
        },
        items: {

            "fold1":{
                "name": "Set Task Type", 
                "items": {
                    "default":{"name": "Default"},
                    "business_rule":{"name": "Business Rule"},
                    "manual":{"name": "Manual"},
                    "receive":{"name": "Receive"},
                     "send":{"name": "Send"},
                     "script":{"name": "Script"},
                     "service":{"name": "Service"},
                     "user":{"name": "User"},
                }
            },
            "fold1a": {
                "name": "Convert to", 
                "items": {
                    "task":{"name": "Task"},
                    "sub_process":  {"name": "Sub-process"},
                     "global_task":  {"name": "Global Task"},
                      "global_process":  {"name": "Global Process"}
                }
            }
        }
    });


}

 var ctr= null; var task_type=null; 
 menu_shape_action = function(action){

if( ctr){
         task_type.removeClass(ctr);
    }  

switch(action){
            case "default":
                $(current).addClass("default");
                ctr= "default";
            break;

            case "business_rule":
                task_type = $(current).addClass("business_rule");
                ctr= "business_rule";
            break;

            case "manual":
                task_type = $(current).addClass("manual");
                ctr= "manual";
            break;

            case "receive":
                task_type = $(current).addClass("receive");
                ctr= "receive";
            break;

            case "send":
                task_type = $(current).addClass("send");
                ctr= "send";
            break;

            case "script":
                task_type = $(current).addClass("script");
                ctr= "script";
            break;

            case "service":
                task_type = $(current).addClass("service");
                ctr= "service";
            break;

            case "user":
                task_type = $(current).addClass("user");
                ctr= "user";
            break;

            default:
              $(current).addClass("default");
              ctr= "default";
            break; 

}

t_type =task_type.attr("ctr",ctr);

}

Answer 1

在您当前的示例中，您可以通过执行task_type.attr("ctr")来访问存储的数据，但实际上您应该使用jQuery方法.data()而不是.attr()。