基于角度中的多个值过滤ng-repeat

时间:2014-10-15 00:14:34

标签: javascript angularjs

这很难说,但是: 我有一个名为users的集合 每个用户都有3个属性:id, name, skill

    {
        _id: 1,
        name: 'frank young',
        skill: 'java'
    },

我有1个表单按回车键收集搜索结果。

<form ng-submit="pushToNewArry(searchTerm)">
    <input type="text" ng-model="searchTerm" />
    <input type="submit">
</form>

这不是执行此操作的最佳方式

$scope.newUsers = [];
$scope.pushToNewArry = function(msg) {
    $scope.trackedUsers.push(msg);
    $scope.searchTerm = '';
};

问题:

如何创建一个将在多个搜索字词上运行的过滤器,并根据users集合与输入值创建匹配的匹配列表。

<ol ng-repeat = "user in users | filter: trackedUsers">
    <li class="names"><span>{{$index}}. </span>{{user.name}}</li>
    <li class="skills">{{user.skill}}</li> 
</ol>

提交后,将保存用户输入并根据搜索的输入值创建users的新数组。因此,多个匹配值。

更新:

JSFiddle

与上面的例子不同,因为我一直在玩它。

1 个答案:

答案 0 :(得分:2)

你的意思是this jsfriddle

更新fiddle

更新fiddle2

<div>{{listSearchTerms | json}}</div>
<form ng-submit="saveSearchTerm()">
    <input type="text" ng-model="searchTerm" />
    <input type="submit">
</form>
<ol  ng-repeat = "user in users | filter:filterSearch(searchTerm)">
    <li class="names"><span>{{$index}}. </span>{{user.name}}</li>
    <li class="skills">{{user.skill}}</li> 
</ol>

的Javascript

var app = angular.module('app', []);

//App.directive('myDirective', function() {});
//App.factory('myService', function() {});

app.controller('MainCtrl', function ($scope) {
    $scope.users = [
        {
            _id: 1,
            name: 'frank young',
            skill: 'java'
        },
        {
            name: 'jeff qua',
            skill: 'javascript'
        },
        {
            name: 'frank yang',
            skill: 'python'
        },
        {
            name: 'ethan nam',
            skill: 'python'
        },
        {
            name: 'ethan nam',
            skill: 'javascript'
        },
    ];
    $scope.searchTerm = "";
    $scope.listSearchTerms = [];
$scope.filterSearch = function (terms) {
    return function (item) {
        return terms.length < 1 ? true : 
        terms.reduce(function (lastresult, term) {
            return lastresult + (item.name.indexOf(term) > -1 || item.skill.indexOf(term) > -1);
        }, 0) > 0;

    }
};
    $scope.saveSearchTerm = function () {
        $scope.listSearchTerms.push($scope.searchTerm);
        $scope.searchTerm = "";
    }
});
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