我目前有两个数据表如下所示:
dt1 <- data.table(urn=c("1","1","1","1","1","1","1","2","2","2","2","3","3","3","3","3","3","3","2"),
date=as.Date(c("2014-01-15","2014-02-15","2014-03-15","2014-04-15","2014-05-15","2014-06-15","2014-07-15",
"2014-04-15","2014-05-15","2014-06-15","2014-07-15",
"2014-04-15","2014-03-15","2014-05-15","2014-02-15","2014-06-14","2014-08-15","2014-07-15","2014-09-16")),
amount=c(20,20,15,15,15,20,25,
15,15,20,20,
30,30,30,30,25,25,25,20))
#dt1
# urn date amount
# 1: 1 2014-01-15 20
# 2: 1 2014-02-15 20
# 3: 1 2014-03-15 15
# 4: 1 2014-04-15 15
# 5: 1 2014-05-15 15
# 6: 1 2014-06-15 20
# 7: 1 2014-07-15 25
# 8: 2 2014-04-15 15
# 9: 2 2014-05-15 15
#10: 2 2014-06-15 20
#11: 2 2014-07-15 20
#12: 3 2014-04-15 30
#13: 3 2014-03-15 30
#14: 3 2014-05-15 30
#15: 3 2014-02-15 30
#16: 3 2014-06-14 25
#17: 3 2014-08-15 25
#18: 3 2014-07-15 25
#19: 2 2014-09-16 20
dt2 <- data.table(urn=c("1","2","3"), lastamount=c(25,20,25),lastchangedate=as.Date(c(NA,NA,NA)))
#dt2
# urn lastamount lastchangedate
# 1: 1 25 <NA>
# 2: 2 20 <NA>
# 3: 3 25 <NA>
需要注意的几件重要事项,(1)骨灰盒总是没有订购,(2)日期总是没有正确订购,(3)金额可能会上升或下降(&) 4)日期可以跳过一个月,(5)日期不总是在一个月的同一天。
我想要达到的目的是更新dt2 lastchangedate以反映更改金额的最新日期(增加或减少)。
所以我希望dt2在处理后看起来如下所示。
#dt2
# urn lastamount lastchangedate
# 1: 1 25 2014-07-15
# 2: 2 20 2014-06-15
# 3: 3 25 2014-06-14
这显然是一个示例数据集。为了给出一个数量级,我的真实dt1有3.5M记录,dt2有250K记录。
由于
更新: 由于我的真实dt2列的数量多于样本中显示的列数,因此我需要能够将它们保留在最终输出中。而不是覆盖dt2的当前实例,我想只是单独更新lastchangedate。以下是我使用的代码。
setkey(dt1, urn) # this is after I had used setkey(dt1, urn, date) to order dt1 properly
setkey(dt2, urn)
dt2[dt1[,list(lastchangedate=max(date[which(diff(amount)!=0)+1])),
by=urn],lastchangedate:=i.lastchangedate]
答案 0 :(得分:1)
这应该这样做:
setkey(dt1, urn, date) ## sort table
dt2 <- dt1[, list(lastamount=amount[.N],
lastchangedate=max(date[which(diff(amount)!=0)+1])),
by=urn]
最后一行查看diff(amount) != 0
的位置并将其偏移一个(发生更改的行的索引)并返回最新日期(max
)。