Question

我想使用通配符功能

如果pattern是* test *且string是 abctestbcd 我必须得到 start index = 3 ， endIndex = 6

Answer 1

试试这段代码：

String searchString = "test";
String s = "abctestbcd";

int startIndex = s.indexOf("test");
int endIndex = startIndex+searchString.length()-1;
System.out.println(startIndex);
System.out.println(endIndex);

如果可以进行多项匹配，请在循环中使用它：

String searchString = "test";
String s = "abctestbcdtest";

int startIndex = -1;
do {
    startIndex = s.indexOf("test", startIndex+1);
    int endIndex = startIndex+searchString.length()-1;
    if (startIndex != -1){
        System.out.println(startIndex);
        System.out.println(endIndex);
    }
} while(startIndex != -1);

Answer 2

Pattern可以帮到你。

Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(text);
// Check all occurrences
while (matcher.find()) {
    System.out.print("Start index: " + matcher.start());
    System.out.print(" End index: " + matcher.end());
    System.out.println(" Found: " + matcher.group());
}

Answer 3

使用subString()和indexOf()函数的组合。

如何从字符串对象获取仅匹配的子字符串start，end index

3 个答案: