我已经使用$ .getJSON在pagebeforeshow上获取json数据,但它不能正常工作。
$(document).on('pagebeforeshow', '#inpGrid', function(e) {
alert("inpGrid");
var tat_url = "http://192.168./html5/Demo/json/list.json";
var url = "http://api.openweathermap.org/data/2.5/forecast?lat=35&lon=139&callback=?" ;
$.getJSON(tat_url, function(res) {
console.log(res)
});
});
代码如上所述,当在$ .getJSON中使用url时,它正在工作,而使用tat_url则无法正常工作。
http://192.168./html5/Demo/json/list.json如下:
{
"response": {
"respCode": 0,
"output": {
"delAction": "OP",
"delTmplt": "sibcVizEdit",
"title": "List TATs",
"layout": "grid",
"srvObjRef": "iawme1/IAWMblztnExpert-ListSIBCs_MB1412577249595",
"startIndex": "0",
"recsPerPage": "18",
"noPages": "1",
"curPageNo": "1",
"fieldInfo": [
{
"label": "Name",
"type": "STRING"
}
{
"label": "Alias",
"type": "STRING"
}
{
"label": "Datatype",
"type": "STRING"
}
{
"label": "Default Value",
"type": "STRING"
}
{
"label": "Visibility",
"type": "STRING"
}
],
"records": [
{
"Name": "psngrType"
"Alias": "Pasngr Type"
"Datatype": "STRING"
"Default Value":"CC"
"Visibility": "0"
},
{
"Name": "flightNo"
"Alias": "Flight No"
"Datatype": "STRING"
"Default Value":"$RV_flightNo"
"Visibility": "0"
}
],
"relServices": {
"AServices": [
{
"ref": "IAWMblztnExpert-ListSIBCs-UpdateBizContext_MB",
"title": "Update SIBC",
"desc": "",
"srvRef": "IAWMblztnExpert-ListSIBCs-UpdateBizContext_MB",
"slctdOffsets": "0"
},
{
"ref": "IAWMblztnExpert-ListSIBCs-ListIICsInSIBC_MB",
"title": "List IICs",
"desc": "",
"srvRef": "IAWMblztnExpert-ListSIBCs-ListIICsInSIBC_MB",
"slctdOffsets": "0"
},
{
"ref": "IAWMblztnExpert-ListSIBCs-Deploy SIBC_MB",
"title": "Deploy",
"desc": "",
"srvRef": "IAWMblztnExpert-ListSIBCs-Deploy SIBC_MB",
"slctdOffsets": "0"
}
]
}
}
}
}
有人可以帮助我,谢谢。
答案 0 :(得分:0)
您的JSON包含语法错误,请查看您的'' fieldInfo''节点。你没有分开你的不同对象,
示例:
{
"label": "Name",
"type": "STRING"
},
{
"label": "Alias",
"type": "STRING"
}
而不是
{
"label": "Name",
"type": "STRING"
}
{
"label": "Alias",
"type": "STRING"
}
如果您需要轻松检查其余的json文件,请使用在线JSON验证器:http://jsonlint.com/