我在我的iOS应用程序中使用嵌入式python解释器。我可以在Xcode控制台中看到print
输出,但我无法看到任何logging.info()
或logging.debug()
输出。我该如何启用它?
我的测试python代码:
import logging
import sys
# try to add logging output to stdout
logging.basicConfig()
log = logging.getLogger()
log.addHandler(logging.StreamHandler())
log.addHandler(logging.StreamHandler(sys.stdout))
# for calling from outside
def main__(args):
print("main__()") # can see output
print type(args)
print len(args)
for eachArg in args:
# print('#: %s' % eachArg) # can see output
logging.info(eachArg) # can NOT see output
输出是:
main__()
<type 'list'>
281
答案 0 :(得分:7)
我认为这些东西是在调试级别。 这段代码适合我:
import logging
import sys
log = logging.getLogger()
log.setLevel(logging.DEBUG)
stream = logging.StreamHandler(sys.stdout)
stream.setLevel(logging.DEBUG)
log.addHandler(stream)
# for calling from outside
def main__(args):
print("main__()") # can see output
print type(args)
print len(args)
for eachArg in args:
logging.info(eachArg)
输出:
>>> main__('test')
main__()
<type 'str'>
4
t
e
s
t
>>>