Question

我的代码就像这样

<body ng-app="">
<div ng-init="friends = [{name:'John', phone:'555-1276'},
                       {name:'Mary', phone:'800-BIG-MARY'},
                       {name:'Mike', phone:'555-4321'},
                       {name:'Adam', phone:'555-5678'},
                       {name:'Julie', phone:'555-8765'},
                       {name:'Juliette', phone:'555-5678'}]"></div>Name only
<input ng-model="search.name">
<br>
    <h3>Results</h3>
<table id="searchObjResults">
    <tr>
        <th>Name</th>
        <th>Phone</th>
    </tr>
    <tr ng-repeat="friendObj in friends | filter:search:strict">
     name:   <input ng-model="friendObj.name" />
        <td>{{friendObj.name}}</td>
         <td>{{friendObj.phone}}</td>
    </tr>
</table>

当发生任何搜索时，我想将结果数据绑定到我提供的输入框。过滤正常，但我无法将其绑定到我的输入。它正确地绑定到<td>。的 Fiddle 谁能告诉我这里做错了什么？

Answer 1

您的输入应该在我认为td之一。看到这个小提琴

http://jsfiddle.net/u08xucsj/

请记住tr只能td

AngularJS中的绑定过滤结果输入失败

1 个答案: