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Question

我试图将图像文件上传到服务器。首先，我将图像路径本地存储在数据库中，然后使用该路径创建一个新文件，并尝试使用http post请求上传图像。它仅适用于2到3个图像文件，如果我尝试连续上传超过3个图像文件，则不会上传文件。我在网络方面有一个非常基本的想法.Plz请给我一个解决方案。

Answer 1

你必须像这样工作

public void connectForMultipart() throws Exception {
    con = (HttpURLConnection) ( new URL(url)).openConnection();
    con.setRequestMethod("POST");
    con.setDoInput(true);
    con.setDoOutput(true);
    con.setRequestProperty("Connection", "Keep-Alive");
    con.setRequestProperty("Content-Type", "multipart/form-data; boundary=" + boundary);
    con.connect();
    os = con.getOutputStream();
}

public void addFormPart(String paramName, String value) throws Exception {
    writeParamData(paramName, value);
}

public void addFilePart(String paramName, String fileName, byte[] data) throws Exception {
    os.write( (delimiter + boundary + "\r\n").getBytes());
    os.write( ("Content-Disposition: form-data; name=\"" + paramName +  "\"; filename=\"" + fileName + "\"\r\n"  ).getBytes());
    os.write( ("Content-Type: application/octet-stream\r\n"  ).getBytes());
    os.write( ("Content-Transfer-Encoding: binary\r\n"  ).getBytes());
    os.write("\r\n".getBytes());

    os.write(data);

    os.write("\r\n".getBytes());
}   
public void finishMultipart() throws Exception {
    os.write( (delimiter + boundary + delimiter + "\r\n").getBytes());
}

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httpPost.setEntity(entity);
HttpResponse response = httpClient.execute(httpPost);

BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "UTF-8"));



String sResponse;
while ((sResponse = reader.readLine()) != null) 
 {
     s = s.append(sResponse);
 }

 if(response.getStatusLine().getStatusCode() == HttpStatus.SC_OK)
 {
     return s.toString();
 }else
 {
     return "{\"status\":\"false\",\"message\":\"Some error occurred\"}";
 }   
} catch (Exception e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}

代替图像，您可以发送任何内容（在您的情况下为image文件），您希望...如果它创建了一些heck然后你应该将大文件分成小部分，然后尝试发送。并在服务器上加入这个小部分。

在我的情况下httpmime-4.2.1-1.jar仅在此代码中需要 enter image description here

Answer 2

参考此

Image Upload and Retrieve Android with WebServices (PHP Code)

Repository包含2个Android项目..图像从Mysql上传到Mysql和Image Retreival 一个文件夹包含webservices和mysql数据库

for Image Upload ...你只需要insert.php

如果它不起作用，请告诉我

Answer 3

    ByteArrayOutputStream stream = new ByteArrayOutputStream();
    //follwing line compress Bitmap image
    image.compress(Bitmap.CompressFormat.JPEG, 90, stream);
    byte[] byteArray = stream.toByteArray();
    String s= Base64.encodeToString(byteArray, Base64.DEFAULT);

这里你将获得一个base64编码的图像，只需将String发送到服务器。你可以从服务器解码图像。

Answer 4

使用它可以帮助你。

try {
        HttpClient client = new DefaultHttpClient();
        HttpPost post = new HttpPost(urlString);
        //FileBody bin = null;
        MultipartEntity reqEntity = new MultipartEntity();
        Bitmap rotatedBitmap2;

        if(rotatedBitmap2 != null){
            Random generator = new Random();
            int n = 10000;
            n = generator.nextInt(n);

            ByteArrayOutputStream bos = new ByteArrayOutputStream();
            rotatedBitmap2.compress(CompressFormat.JPEG, 75, bos);
            byte[] data = bos.toByteArray();
            ByteArrayBody bab = new ByteArrayBody(data,"dcc/"+n+".jpg");

            reqEntity.addPart("Image", bab);            
        }               
        post.setEntity(reqEntity);
        HttpResponse response = client.execute(post);
        HttpEntity resEntity = response.getEntity();
        response_str = EntityUtils.toString(resEntity);
        if (resEntity != null) {
            //do some work
        }
    } catch (Exception ex) {
        Log.e("Debug", "error: " + ex.getMessage(), ex);
    }       
}

将图像文件上传到服务器android

4 个答案:

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