Question

您好我一直在互联网上混合和匹配代码，试图制作一个递归搜索目录的命令。我现在很困难。目前我的目录中只有两个文件（没有子目录），我的打印输出一直显示我有比实际更多的文件。

这是我的打印输出：

entered
entered
entered
enteredIF
entered
enteredIF
entered
enteredIF
entered
enteredIF

我认为它应该做的只是打印进入IF两次。有趣的是，我的两个文件中有11个字符，并且有11个打印语句。也许这与我的问题有某种关系。

有谁能告诉我如何获得两个打印输出（每个文件一个）？

#include <stdio.h>
#include <unistd.h>
#include <termios.h> 
#include <dirent.h>
/* A process is a single process.  */ 
typedef struct process
{
  struct process *next;       /* next process in pipeline */
  char **argv;                /* for exec */
  pid_t pid;                  /* process ID */
  char completed;             /* true if process has completed */
  char stopped;               /* true if process has stopped */
  int status;                 /* reported status value */
} process;
/* A job is a pipeline of processes.  */
typedef struct job
{
  struct job *next;           /* next active job */
  char *command;              /* command line, used for messages */
  process *first_process;     /* list of processes in this job */
  pid_t pgid;                 /* process group ID */
  char notified;              /* true if user told about stopped job */
  struct termios tmodes;      /* saved terminal modes */
  int stdin, stdout, stderr;  /* standard i/o channels */
} job;

/* The active jobs are linked into a list.  This is its head.   */
job *first_job = NULL;


int main(int argc, char** argv) {
    // char cwd[1024]; // buffer
    // char* sdirectory = getcwd(cwd, sizeof(cwd)); 
    // printf("dir name: %s\n", sdirectory);

    int file_count = 0;
    DIR* dirp;
    struct dirent* entry;

    dirp = opendir(".");

    while ((entry = readdir(dirp)) != NULL) {
        printf("entered\n");
        if (entry-> d_type == DT_REG) {
        printf("enteredIF\n");
        file_count++;
    }

}
    closedir(dirp);
    printf("file count: %d\n", file_count);

}

Answer 1

将输入的printf更改为：printf("saw filename '%s'\n", entry->d_name);，然后您就可以看到它认为正在阅读的文件名。也许你有更多的点文件而不仅仅是.和..。 - JohnH

从头开始创建grep命令

1 个答案: