您好我有以下字符串
{
"data1" : "sample data",
"data2" : "sample data2"
}
我想使用字符串库将上面的字符串拆分为
data1
sample data
以下是我提出的代码,但它只是向左和向右分裂。上面的数据存储在缓冲区中并由line_number迭代。
if(pos != std::string::npos)
{
newpos = buffer[line_number].find_first_of(":",pos);
token = buffer[line_number].substr(pos + 1,newpos-pos-1);
pos = newpos + 1;
std::cout << token << std::endl;
}
非常感谢帮助。
答案 0 :(得分:0)
非常简单的解析器可能如下所示:
#include <iostream>
#include <string>
#include <vector>
#include <map>
using namespace std;
static string& strip(string& s, const string& chars = " ")
{
s.erase(0, s.find_first_not_of(chars.c_str()));
s.erase(s.find_last_not_of(chars.c_str()) + 1);
return s;
}
static void split(const string& s, vector<string>& tokens, const string& delimiters = " ")
{
string::size_type lastPos = s.find_first_not_of(delimiters, 0);
string::size_type pos = s.find_first_of(delimiters, lastPos);
while (string::npos != pos || string::npos != lastPos) {
tokens.push_back(s.substr(lastPos, pos - lastPos));
lastPos = s.find_first_not_of(delimiters, pos);
pos = s.find_first_of(delimiters, lastPos);
}
}
static void parse(string& s, map<string,string>& items)
{
vector<string> elements;
s.erase(0, s.find_first_not_of(" {"));
s.erase(s.find_last_not_of("} ") + 1);
split(s, elements, ",");
for (vector<string>::iterator iter=elements.begin(); iter != elements.end(); iter++) {
vector<string> kv;
split(*iter, kv, ":");
if (kv.size() != 2) continue;
items[strip(kv[0], " \"")] = strip(kv[1], " \"");
}
}
int
main()
{
string data = " { \"key1\" : \"data1\" , \"key2\" : \"data2\" } ";
map<string,string> items;
parse(data, items);
for (map<string,string>::iterator iter=items.begin(); iter != items.end(); iter++) {
cout << "key=" << (*iter).first << ",value=" << (*iter).second << endl;
}
}