Question

我试图以这样的方式对字符串进行标记：...

示例字符串

Public Static void main(String[args])

String tokenizer tokenize like

public
static
void
main
String
args

但我想以这种方式进行标记化

public

static

void

main
(
String
[
args
]
)

表示它还会打印字符串移动到标记化

的字符

Answer 1

public String[] tokenise(String str){
    String progress = "";
    LinkedList<String> list = new LinkedList<String>();
    for(int c = 0; c < str.length(); c++){
            char ch = str.charAt(c);
            // Skip next char if the current char is an escape character
            if(ch == '\\'){
                c++;
                continue;
            }
            // If current char is to be tokenised, add progress and char to list
            if(ch == ' ' || ch == '(' || ch == ')' || ch == '[' || ch == ']'){
                    if(!progress.equals("")) list.add(progress);
                    list.add(ch+"");
                    progress = "";
            }else{ 
                progress += ch;
            }
    }
    String[] result = new String[list.size()];
    for(int c = 0; c < result.length; c++) result[c] = list.get(c);
    return result;
}

Answer 2

import java.util.Scanner;
import java.util.ArrayList;

public class SOQ17
{

   public Scanner scan;

   public String test;

   public boolean check = true;

   public SOQ17()
   {

      System.out.print("Enter your string.\n");

      scan = new Scanner(System.in);

      test = scan.nextLine();

      for(int i = 0; i < test.length(); i++)
      {

         if((test.charAt(i) >= 'A' && test.charAt(i) <= 'Z') || (test.charAt(i) >= 'a' && test.charAt(i) <= 'z'))
         {

            System.out.print(test.charAt(i) + "");
            check = true;

         }

         else
         {

            if(check)
            {

               System.out.println("");

            }

            System.out.println(test.charAt(i));
            check = false;

         }

      }

   }

   public static void main(String[] args)
   {

      while(true)
      {

         SOQ17 soq = new SOQ17();

      }

   }

}

以下是我的工作方式，它将为每一件不是字母的东西创造一条新线。但是，如果它是一封信，它只会将其打印出来。另外，我使用布尔'检查'来确保在字母之间来回交替时应用正确的格式。

用特殊字符解析java中的字符串

2 个答案: