我已经制作了一个用于解析URL数据的Android应用程序。只要在返回的json数据中没有引号,应用程序就可以正常工作。当数据有这样的标记时,有没有办法用Java解析json数据:
{
"cate":
[
{
"title": "this is the "title" like ",
"EdId": "445",
"date": "Sep 25, 2014"
}
]
}
以下是我正在使用的代码:
public class Guys extends Activity {
ListView list;
TextView title;
TextView EdId;
TextView date;
Button Btngetdata;
//Button nextac;
ArrayList<HashMap<String, String>> oslist = new ArrayList<HashMap<String, String>>();
//URL to get JSON Array
private static String url = "http://10.10.10.2/test/ff.php";
//JSON Node Names
//private static final String ca
private static final String TAG_CAT = "cate";
private static final String TAG_TITLE = "title";
private static final String TAG_EDID = "EdId";
private static final String TAG_DATE = "date";
JSONArray cate = null;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.test_main);
oslist = new ArrayList<HashMap<String, String>>();
new JSONParse().execute();
}
private class JSONParse extends AsyncTask<String, String, JSONObject> {
private ProgressDialog pDialog;
@Override
protected void onPreExecute() {
super.onPreExecute();
title = (TextView)findViewById(R.id.title);
EdId = (TextView)findViewById(R.id.edid);
date = (TextView)findViewById(R.id.date);
pDialog = new ProgressDialog(Guys.this);
pDialog.setMessage("Getting Data ...");
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();
}
@Override
protected JSONObject doInBackground(String... args) {
String jn="ff'f'd";
JSONParser jParser = new JSONParser();
// Getting JSON from URL
JSONObject json = jParser.getJSONFromUrl(url);
json.toString();
return json;
}
@Override
protected void onPostExecute(JSONObject json) {
pDialog.dismiss();
try {
//json = json.substring(7);
// Getting JSON Array from URL
cate = json.getJSONArray(TAG_CAT);
for(int i = 0; i < cate.length(); i++){
JSONObject c = cate.getJSONObject(i);
// Storing JSON item in a Variable
String title = c.getString(TAG_TITLE);
String EdId = c.getString(TAG_EDID);
//String date = c.getString(TAG_API);
// Adding value HashMap key => value
HashMap<String, String> map = new HashMap<String, String>();
map.put(TAG_TITLE, title);
map.put(TAG_EDID, EdId);
//map.put(TAG_API, date);
oslist.add(map);
list=(ListView)findViewById(R.id.list);
ListAdapter adapter = new SimpleAdapter(Guys.this, oslist,
R.layout.list_v,
new String[] { TAG_TITLE}, new int[] {
R.id.title});
list.setAdapter(adapter);
list.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
Toast.makeText(Guys.this, "You Clicked at "+oslist.get(+position).get("EdId"), Toast.LENGTH_SHORT).show();
Intent myIntent = new Intent(Guys.this, SimpleBrowser.class);
String idurl = oslist.get(+position).get("EdId");
String idsend = idurl;
myIntent.putExtra("id",idurl.toString());
Guys.this.startActivity(myIntent);
}
});
}
} catch (JSONException e) {
e.printStackTrace();
}
}
}
}
答案 0 :(得分:1)
我认为问题在于系统产生json
字符串,在生产者系统中,您需要转义"
字符,将其替换为\"
或使用{{1}而是charachter。
答案 1 :(得分:0)
您可以使用gson类来解析json响应。 你需要创建一个类
class Data{
ArrayList<Data> cate;
getCateList(){
return cate;
}
String title;
String EdId;
String date;
}
InputStream source = retrieveStream(url);
Gson gson = new Gson();
Reader reader = new InputStreamReader(source);
Data response = gson.fromJson(reader, Data.class);
阅读以下教程:http://www.javacodegeeks.com/2011/01/android-json-parsing-gson-tutorial.html