为复合PK生成的null id

Question

我还有以下表和以下关系表：，它有一个复合PK如下：

UserRole.java

@RooJavaBean
@RooJpaEntity(identifierType = UserRolePK.class, versionField = "", table = "UserRole", schema = "dbo")
@RooDbManaged(automaticallyDelete = true)
@RooToString(excludeFields = { "idApplication", "idRole", "idUserName" })
public class UserRole {
}

UserRole_Roo_DbManaged.aj

@ManyToOne
@JoinColumn(name = "IdApplication", referencedColumnName = "IdApplication", nullable = false, insertable = false, updatable = false)
private Application UserRole.idApplication;

@ManyToOne
@JoinColumn(name = "IdRole", referencedColumnName = "IdRole", nullable = false, insertable = false, updatable = false)
private Role UserRole.idRole;

@ManyToOne
@JoinColumn(name = "IdUserName", referencedColumnName = "IdUserName", nullable = false, insertable = false, updatable = false)
private Users UserRole.idUserName;

但也存在PK表：

@RooIdentifier(dbManaged = true)
public final class UserRolePK {}

及其标识符类（UserRolePK_Roo_Identifier.aj）

privileged aspect UserRolePK_Roo_Identifier {

    declare @type: UserRolePK: @Embeddable;

    @Column(name = "IdRole", nullable = false)
    private Long UserRolePK.idRole;

    @Column(name = "IdUserName", nullable = false, length = 16)
    private String UserRolePK.idUserName;

    @Column(name = "IdApplication", nullable = false)
    private Long UserRolePK.idApplication;

我将服务目标设置为保存的方式是：

UserRole userRole= new UserRole();
userRole.setIdApplication(app);
userRole.setIdRole(invited);
userRole.setIdUserName(user);
appService.saveURole(userRole);

app 已设置并保存（同一交易），以及 邀请 和 用户 对象。 由于user（来自Users表的复合PK：IdUserName是一个String）定义如下，否则不起作用。

@RooJavaBean
@RooJpaEntity(versionField = "", table = "Users", schema = "dbo")
@RooDbManaged(automaticallyDelete = true)
@RooToString(excludeFields = { "quotations", "taxes", "userRoles", "idCompany", "idPreferredLanguage" })
public class Users {

    @Id
    //@GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "IdUserName", length = 16, insertable = true, updatable = true)
    private String idUserName;
}

所以，我得到的错误是：

org.springframework.orm.jpa.JpaSystemException: org.hibernate.id.IdentifierGenerationException: null id generated for:class com.domain.UserRole; nested exception is javax.persistence.PersistenceException: org.hibernate.id.IdentifierGenerationException: null id generated for:class com.domain.UserRole

Answer 1

试试这个：

public class UserRole {
   @PrePersist
   private void prePersiste() {
       if (getId() == null) {
           UserRolePK pk = new UserRolePK();
           pk.setIdApplication(getIdApplication());
           pk.setIdRole(getIdRole);
           pk.setIdUserName(getIdUserName());
           setId(pk);
       }
   }
}

Roo正在UserRole实体及其id嵌入类生成字段，但不一样（UserRole.idRole与UserRole.id.idRole不同）。在您的示例中，您填写UserRole字段，但不填写id字段。此代码在实体持久化之前为您提供。

祝你好运！

Answer 2

在我的情况下，如果以下示例尝试保留在数据库中，则会引发上面提到的类似异常：

EntityExample e = new EntityExample();
repositoryExample.save(e);
//throw ex

这是由于缺少ID字段值而引起的，需要将其设置为以下内容：

EntityExample e = new EntityExample();
e.setId(new EmbeddedIdExample(1, 2, 3));
repositoryExample.save(e);