我必须从posts
表
有foreign keys
(
category_id
categories.id
提到created_by
users.id
对updated_by
的引用,
users.id
对created_by
的引用
)
我可以抓取username
$this->Post->Behaviors->load('Containable');
$this->paginate = array(
'conditions' => array('Post.category_id' => $id),
'order' => array('title'),
'contain' => array(
'User'=>array(
'fields'=>array('id','first_name','last_name','username'),
'conditions' => array('User.id = Post.created_by')
),
//posts table has 2 fields(created_by & updated_by) associated with users table
//'User'=>array(
// 'fields'=>array('id','first_name','last_name','username'),
// 'conditions' => array('User.id = Post.updated_by')
// ),
'Category'=>array(
'Type'=>array(
'fields'=>array('id','type_name')
)
),
)
);
但不能同时抓取
public $belongsTo = array(
'User'=> array(
'className' => 'User',
'foreignKey' => 'created_by',
'foreignKey' => 'updated_by'
),
);
//发布模型
public $hasMany = array(
'Post' => array(
'className' => 'Post',
'foreignKey' => array('created_by','updated_by'),
),
);
//用户模型
created_by
如何将用户同时显示为(updated_by
& {{1}})
答案 0 :(得分:2)
首先,您需要在Post模型中定义两个关系
public $belongsTo = array(
'CreatedUser'=> array(
'className' => 'User',
'foreignKey' => 'created_by'
),
'UpdatedUser'=> array(
'className' => 'User',
'foreignKey' => 'updated_by'
)
);
现在在用户模型中创建逆向关系。
public $hasMany = array(
'CreatedPosts' => array(
'className' => 'Post',
'foreignKey' =>'created_by'
),
'UpdatedPosts' => array(
'className' => 'Post',
'foreignKey' => 'updated_by'
),
);
然后是find()
$this->Post->Behaviors->load('Containable');
$this->paginate = array(
'conditions' => array('Post.category_id' => $id),
'order' => array('title'),
'contain' => array(
'CreatedUser'=>array(
'fields'=>array('id','first_name','last_name','username')
),
'UpdatedUser'=>array(
'fields'=>array('id','first_name','last_name','username')
),
'Category'=>array(
'Type'=>array(
'fields'=>array('id','type_name')
)
),
)
);