我有2张桌子
表1结构:[日志]
userid ||点击||日期|| XXX || XXX |||
表2结构:[用户]
用户名||电子邮件||日期|| XXX || XXX |||
我想显示这样的数据
用户名,COUNT(点击次数)
我正在使用下面的查询。
SELECT `user.username`,`userid`, COUNT(`userid`) as `total`
FROM `logs`
INNER JOIN user ON logs.userid=user.userid
ORDER BY total DESC
LIMIT 5
请定义
在第一次回复之后,我修改了查询并提供了它,就像这个
$sqlptcwall=mysql_query("SELECT user.username, COUNT(ptcwalllogs.userid) AS total FROM logs INNER JOIN user ON user.userid = ptcwalllogs.userid GROUP BY user.username ORDER BY COUNT(ptcwalllogs.userid) DESC
LIMIT 5");
<?php
echo "</tr>";
while($row = mysql_fetch_array($sqlptcwall))
{
echo "<tr> ";
echo "<td>" .$row[userid] . "</td>";
echo "<td>" .$row[total] . "</td>";
}
echo "</tr> " ;
?>
错误: mysql_fetch_array()期望参数1是资源,在
中给出布尔值答案 0 :(得分:1)
SELECT user.username, COUNT(user.userid) AS total
FROM logs
INNER JOIN user ON user.userid = logs.userid
GROUP BY user.username
ORDER BY COUNT(user.userid) DESC
LIMIT 5