Question

如何在SQL Server中的两个已知字符序列之间剪切子字符串？

例如：这是我的字符串（表格中的列）

＆＃39; DateTimeFormat = dd.MM.yyyy＆amp; ReportDate_FromDate = 08/11/2014 00:00:00＆amp; ReportDate_ToDate = 08/12/2014 23：59：00＆amp; Reports_Brand：isnull = true＆amp; Reports_Portal：isnull =真安培; Reports_Currency：ISNULL =真安培; ReportBy = WEEK＆安培;排序依据：ISNULL =真安培; IncludeDataForLastHour：ISNULL =真安培;服务器名称：ISNULL =真安培;用户= pirman1＆安培; Reports_Export =假＆安培;内＆＃39;

我希望仅查看pirman1与&User=之间的&。

Answer 1

substring和charindex的组合应该可以解决问题：

SELECT SUBSTR(str_col, start_pos, end_pos - start_pos + 1)
FROM   (SELECT str_col,
               CHARINDEX('&User=', str_col) AS start_pos, 
               CHARINDEX('&', str_col, CHARINDEX('&User=', str_col) + 1) AS end_pos
        FROM   my_table) t

Answer 2

我已经测试了这段代码，对Mureinik的代码略有改动，这个代码工作得很好。

 SELECT REPLACE(REPLACE(SUBSTRING(string, start_pos,  end_pos - start_pos  
    +1), '&User=', ''), '&', '')

   FROM   (SELECT string,
           CHARINDEX('&User=', string) AS start_pos, 
           CHARINDEX('&', string, CHARINDEX('&User=', string)+1)  AS end_pos
           FROM dbo.TestTbl
      ) AS abc

如何在SQL Server中的已知字符之间剪切子字符串

2 个答案: