Question

我试图获得点击/用户到我的网站的数量，为此我有他们的cookie ID和日期。但是从我到目前为止所写的查询中我得到以下错误

表

cookieid  date      
--------------------
001       2011-03-17          
001       2011-03-17         
002       2011-03-17          
001       2011-03-17          
001       2011-03-20
002       2011-03-21    
114       2011-03-21          
114       2011-03-21

计数应表明的确切方式是：

on 2011-03-17 => 4 clicks / 2 unique visitors
on 2011-03-20 => 1 click  / 1 unique visitor   
on 2011-03-21 => 3 clicks / 2 unique visitors

如果我在查询中确实如此

"INSERT INTO visitos SELECT cookieid,date FROM ",@tab," GROUP BY cookieid"

这通过正确计数给出了点击/用户的正确计数，但它忽略了日期，根据上表它将告诉2011-03-17 =＆gt; 4次点击/ 2次唯一身份访问者但忽略了20次点击/访问，并且没有计算20次。因为cookie id正在重复

用另一种方式

"INSERT INTO visitos SELECT cookieid,date FROM ",@tab," GROUP BY date"

它会给出点击/访问的所有日期，但计数的结果是错误的，它会告诉2011-03-17 =＆gt; 4次点击/ 4位唯一身份访问者，将每次点击作为唯一身份用户，同时忽略Cookie ID

任何人都可以帮我编写SQL查询，以便通过cookie id和日期立即对此进行分组

P.S "INSERT INTO visitos SELECT cookieid,date FROM ",@tab," GROUP BY date,cookieid"

无效

存储过程

BEGIN
SET @tab = CONCAT("monitortable_",pr);
DROP TABLE IF EXISTS uniquevisitors;
CREATE TEMPORARY TABLE uniquevisitors (`cookieid` INT, `date` DATETIME);


**SET @sqlstring = CONCAT("(PLACE WHERE GROUPING QUERY SHOULD TAKE PLACE)INSERT INTO uniquevisitors SELECT cookieid,date FROM ",@tab," GROUP BY cookieid");**


PREPARE stmt FROM @sqlstring;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
DROP TABLE IF EXISTS uniquevisitorscount;
CREATE TEMPORARY TABLE uniquevisitorscount (`cnt` INT, `dat` DATETIME);
INSERT INTO uniquevisitorscount SELECT COUNT(cookieid) AS cnt ,DATE(date) AS dat FROM uniquevisitors;
DROP TABLE IF EXISTS nonuniquevisitcount;
CREATE TEMPORARY TABLE nonuniquevisitcount (`cnt` INT, `dat` DATETIME);
SET @sqlstring = CONCAT("INSERT INTO nonuniquevisitcount SELECT COUNT(cookieid) AS cnt ,DATE(date) AS dat 

FROM ",@tab," GROUP BY DATE_FORMAT(date, '%y'),DATE_FORMAT(date, '%m'),DATE_FORMAT(date, '%d')");
    PREPARE stmt FROM @sqlstring;
    EXECUTE stmt;
    SELECT un.cnt AS ucnt, nu.cnt AS cnt, un.dat AS dat FROM uniquevisitorscount un JOIN nonuniquevisitcount nu ON un.dat = nu.dat;
END$$

Answer 1

试试这个

“INSERT INTO visitos date，count（cookie_id）no_of_clicks，count（distinct cookie_id）no_of_visitors FROM”，@ tab，“GROUP BY date”

Answer 2

试试这个：

select x.date, sum(x.cnt) as clicks, count(*) as uniqueVisitors from
    (select date, cookieid, count(*) as cnt from #temp group by date, cookieid) x 
    group by x.date

返回：

date        clicks  uniqueVisitors
2011-03-17  4       2
2011-03-20  1       1
2011-03-21  3       2

完全按照你的意愿......你只需要创建一个插入语句......

多个分组SQL，点击次数和用户数错误

2 个答案: