matplotlib errorbar plot - 使用自定义色彩映射

Question

我试图为沿x轴的每个点制作一个不同颜色的误差线图。错误条形图本身很好，但是当我尝试使用色彩映射时它会爆炸，所以我一定做错了。这是我尝试做的一个人为的例子：

import matplotlib.pyplot as plt

colors = ["b","g","c","m","y","k","r","g","c","m","y","k",
          "b","g","c","m","y","k","r","g","c","m","y","k"]

xlabels = ['A','B','8','14']

xval = [0, 1, 2, 3]
yval = [0, 1, 4, 9]
yerr = [0.5, 0.4, 0.6, 0.9]


cmap = dict(zip( xval,colors))

现在我跑完之后我可以去：

plt.errorbar(xval, yval, yerr=yerr, color='b')

这给了我下面显示的图表（即它有效。但是当我尝试这样做时：

plt.errorbar(xval, yval, yerr=yerr, color=cmap)

它给了我一个错误，比如＆＃34; ValueError：to_rgba：无效的rgba arg＆＃34; {0：＆＃39; b＆＃39;，1：＆＃39; g＆＃39;，2：＆＃39; c＆＃39;，3：＆＃39 ;米＆＃39;}＆＃34;

有可能做我尝试做的事情吗？我想做的是让错误栏图表中的每个点都有不同的颜色。我真的不需要连接点的线。感谢任何帮助/建议。

Answer 1

我已经提到过你可以遍历每个特定的点/颜色。

另一种解决方案是在scatter图中使用errorbar图，就像在此question中一样。代码在

之下

import matplotlib.pyplot as plt

colors = ["b","g","c","m","y","k","r","g","c","m","y","k",
          "b","g","c","m","y","k","r","g","c","m","y","k"]

xlabels = ['A','B','8','14']

xval = [0, 1, 2, 3]
yval = [0, 1, 4, 9]
yerr = [0.5, 0.4, 0.6, 0.9]

plt.scatter(xval, yval, c=colors, s=50, zorder=3)
plt.errorbar(xval, yval, yerr=yerr, zorder=0, fmt="none",
             marker="none")

plt.savefig("scatter_error.png", dpi=300)
plt.show()

具有以下结果