使用scale_colour_manual()
,可以从RColorBrewer中选择特定颜色作为颜色值吗?
例如,在:
scale_colour_manual(breaks=c("A","B","C","D","E"),
values=c("green","orange","blue","pink","yellow"))
我想使用调色板scale_colour_brewer(type = "qual", palette = 7)
中的第一种颜色而不是"绿色",然后使用调色板scale_colour_brewer(type = "qual", palette = 2)
的第四种颜色而不是&#34 ;橙"等等。
答案 0 :(得分:17)
我经常做以下事情,
library(RColorBrewer)
my_palette = c(brewer.pal(5, "Set1")[c(1,3,4,5)], brewer.pal(5, "Pastel1")[c(2,5,1,3)])
#grid::grid.raster(my_palette, int=F)
scale_colour_discrete = function(...) scale_colour_manual(..., values = palette())
dsamp <- diamonds[sample(nrow(diamonds), 1000), ]
(p <- qplot(carat, price, data = dsamp, colour = clarity)) # default palette
palette(my_palette)
p # custom colors