Question

我有一个CustomerAddForm和一个CustomerOverview HTML表。当我在CustomerAddForm中添加新记录时，它将显示在CustomerOverview HTML表中。我还具有通过单击客户名称从CustomerOverview HTML打开现有客户的功能。

当我打开现有客户时，它会打开客户，但是当我点击提交时，它会将已打开的客户保存到新记录中。如果我在视图中对客户ID进行硬编码，则会保存给定的ID。因此，在点击提交时看起来没有推送ID。

正常;

def customeradd(request, id = None)

使用硬编码ID;

def customeradd(request, id = 1)

我的观点.py;点击提交request.method =='POST'似乎总是如此。并且else语句永远不会运行。

def customeradd(request, id = None): 
    if id:
        customer = Customer.objects.get(pk = id)
    else:
        customer = None

    if request.method == 'POST':
        form = CustomerAddForm(request.POST or None, instance = customer)
        if form.is_valid():
            save_it = form.save(commit=False)
            save_it.save()
            messages.success(request, 'Customer added succesfully')
            return HttpResponseRedirect('/customeroverview/')
        else:
            messages.error(request, 'Customer save error, please check fields below')
    else:
        form = CustomerAddForm(instance = customer)
        if form.is_valid():
            form.save()
            messages.success(request, 'Customer edited succesfully')
            return HttpResponseRedirect('/customeroverview/')

    return render_to_response("customer-add.html",
                              {"customer_add_form": form},
                              context_instance=RequestContext(request))

my forms.py（django-crispy-form）

class CustomerAddForm(forms.ModelForm):
    def __init__(self, *args, **kwargs):
        super(CustomerAddForm, self).__init__(*args, **kwargs)
        self.helper = FormHelper(self)
        self.helper.form_action = '/customeradd/'     

        self.helper.add_input(Submit('submit', 'Submit'))
        self.helper.add_input(Button('cancel', 'Cancel'))

    class Meta:
        model = Customer

my urls.py

url(r'^customeroverview/$', 'customer.views.customeroverview', name='customeroverview'),
url(r'^customeradd/$', 'customer.views.customeradd', name='customeradd'),
url(r'^customeradd/(?P<id>\w+)$', 'customer.views.customeradd', name='customeredit'),

客户add.html

{% block content %}

{% load crispy_forms_tags %}
{% crispy customer_add_form customer_add_form.helper %}


{% endblock %}

Answer 1

使用它：

def customeradd(request, id=None): 
    if id:
        customer = Customer.objects.get(pk = id)
    else:
        customer = Customer()

    if request.method == 'POST':
        form = CustomerAddForm(request.POST, instance=customer)
        if form.is_valid():
            form.save()
            messages.success(request, 'Customer added succesfully')
            return HttpResponseRedirect('/customeroverview/')
        else:
            messages.error(request, 'Customer save error, please check fields below')
    else:
        form = CustomerAddForm(instance = customer)

    return render_to_response("customer-add.html",
                              {"customer_add_form": form},
                              context_instance=RequestContext(request))

并替换

self.helper.form_action = '/customeradd/'

与

self.helper.form_action = ''

在forms.py

中

Answer 2

您可以使用特定功能编辑客户：

@require_POST
@csrf_protect
def customeredit(request, id=None): 

    edited_customer = CustomerAddForm(request.POST)

    if edited_customer.is_valid():
        customer = edited_customer.save(commit=False)
        customer.id = id
        customer.save()
        messages.success(request, 'Customer edited succesfully')
        return HttpResponseRedirect('/customeroverview/')
    else:
        messages.error(request, 'Customer save error, please check fields below')
        return render_to_response("customer-add.html",
                          {"customer_add_form": edited_customer},
                          context_instance=RequestContext(request))

这意味着您需要修改urls.py

url(r'^customeredit/(?P<id>\w+)$', 'customer.views.customeraedit', name='customeredit'),

Django打开/编辑记录而不是创建新记录

2 个答案: