Question

在<Images>代码中，this API call会返回不同类型的混合：fanart，boxart，banner，screenshot，clearlogo。

使用SimpleXML Framework，将这些解析为单独的列表的最佳方法是什么？我想要List<FanArt>，List<BoxArt>，List<Banner>等。网站上的examples似乎并未涵盖这种情况。我已经摸索了一些不同的想法，但我甚至不确定SimpleXML Framework是否可以直接处理这个问题。

例如，下面引发了这个异常： org.simpleframework.xml.core.PersistenceException：在字段'clearLogos'上复制名称'Images'的注释.....

@ElementList(name = "Images", entry = "clearlogo")
private List<ClearLogo> clearLogos;

@ElementList(name = "Images", entry = "boxart")
private List<BoxArt> boxart;

Answer 1

如果有人遇到这种情况并需要某种解决方案，我现在就已经完成了这项工作。这份工作，但它不是我真正想要的。

@Root
public class Images {

@ElementListUnion({
        @ElementList(entry = "fanart", type = FanArt.class, inline = true),
        @ElementList(entry = "boxart", type = BoxArt.class, inline = true),
        @ElementList(entry = "screenshot", type = ScreenShot.class, inline = true),
        @ElementList(entry = "banner", type = Banner.class, inline = true),
        @ElementList(entry = "clearlogo", type = ClearLogo.class, inline = true)
})
private List<Object> images;

private List<FanArt> fanarts;

private List<BoxArt> boxarts;

private List<ScreenShot> screenshots;

private List<Banner> banners;

private List<ClearLogo> clearlogos;

public List<FanArt> getFanarts() {
    if (fanarts == null) {
        fanarts = new ArrayList<FanArt>();
        for (Object image : images) {
            if (image instanceof FanArt) {
                fanarts.add((FanArt) image);
            }
        }
    }
    return fanarts;
}

public List<BoxArt> getBoxarts() {
    if (boxarts == null) {
        boxarts = new ArrayList<BoxArt>();
        for (Object image : images) {
            if (image instanceof BoxArt) {
                boxarts.add((BoxArt) boxarts);
            }
        }
    }
    return boxarts;
}

public List<ScreenShot> getScreenshots() {
    if (screenshots == null) {
        screenshots = new ArrayList<ScreenShot>();
        for (Object image : images) {
            if (image instanceof ScreenShot) {
                screenshots.add((ScreenShot) image);
            }
        }
    }
    return screenshots;
}

public List<Banner> getBanners() {
    if (banners == null) {
        banners = new ArrayList<Banner>();
        for (Object image : images) {
            if (image instanceof Banner) {
                banners.add((Banner) image);
            }
        }
    }
    return banners;
}

public List<ClearLogo> getClearLogos() {
    if (clearlogos == null) {
        clearlogos = new ArrayList<ClearLogo>();
        for (Object image : images) {
            if (image instanceof ClearLogo) {
                clearlogos.add((ClearLogo) image);
            }
        }
    }
    return clearlogos;
}
}

使用SimpleXML解析混合列表

1 个答案: