使用cassandra中的列名获取值

时间:2014-10-09 07:52:20

标签: php cassandra

您好我正在使用php和cassandra数据库。我想从cassandra数据库获取用户名和密码。它返回以下结果。

Cassandra\Rows Object(
[columns:protected] => Array
    (
        [0] => Cassandra\ColumnSpec Object
            (
                [keyspace:protected] => team1_groupboxx
                [tablename:protected] => gb_adminusers
                [name:protected] => au_username
                [type:protected] => Cassandra\TypeSpec Object
                    (
                        [type:protected] => 13
                        [customTypename:protected] => 
                        [keyType:protected] => 
                        [valueType:protected] => 
                    )

            )

        [1] => Cassandra\ColumnSpec Object
            (
                [keyspace:protected] => team1_groupboxx
                [tablename:protected] => gb_adminusers
                [name:protected] => au_password
                [type:protected] => Cassandra\TypeSpec Object
                    (
                        [type:protected] => 13
                        [customTypename:protected] => 
                        [keyType:protected] => 
                        [valueType:protected] => 
                    )

            )

    )

[rowCount:protected] => 1
[columnCount:protected] => 2
[current:protected] => 0
[rows:protected] => Array
    (
        [0] => Array
            (
                [0] => k2badmin
                [1] => f2c452187d4af19966187e15f1e944e1
            )

    )

但我想以下面的格式获取查询结果。

Array (
       [au_username] => admin
       [au_password] => f2c452187d4af19966187e15f1e944er              

  )

其中au_username和au_password是我的表的列名。

0 个答案:

没有答案