Question

尝试获取选定的行项目。我一直认为它应该有效：

<DataGrid ItemsSource="{Binding Path=Customers}"
              SelectedItem="{Binding Path=SelectedCustomer, Mode=TwoWay}"/>

Customer customer = (Customer)myDataGrid.SelectedItem;

在第一个xaml中 - 我说它，它没有错误或我不知道如何使用它的东西..如何在c＃代码中我可以获得所选行？
在C＃行代码中出错。视觉工作室并不存在客户。

我会感谢你的帮助。 :)谢谢。

Answer 1

网格定义非常不完整。理事会明确所有用个人约束构成的列

在这种情况下，我使用事件doubleClick，但您必须为您选择正确的事件

以代码为例，试试这个：

在XAML中添加：

<DataGrid x:Name="MyDataGrid" x:FieldModifier="public" MouseDoubleClick="MyDataGrid_MouseDoubleClick" ItemsSource="{Binding Path=Customers}" 
              SelectedItem="{Binding Path=SelectedCustomer, Mode=TwoWay}"/>

在c＃后面编写代码：

private void MyDataGrid_MouseDoubleClick(object sender, MouseButtonEventArgs e)
        {
            if (sender != null)
            {
                DataGrid grid = sender as DataGrid;
                if (grid != null && grid.SelectedItems != null && grid.SelectedItems.Count == 1)
                {

                        var selectedRow = grid.SelectedItem as MyObject;

                        try
                        {
                            Mouse.OverrideCursor = Cursors.Wait;

                            //TODO YOUR OPERATION ON selectdRow
                        }
                        finally
                        {
                             Mouse.OverrideCursor = null;
                        }

                }
            }
        }

Answer 2

很难知道你究竟想要什么:)但是这里有一个例子我只是想知道如何将信息拖出数据网格。没有在其中植入很多那些绑定，所以这是纯粹的信息。

<强>的Xaml

<Grid>
    <Grid.RowDefinitions>
        <RowDefinition Height="*" />
        <RowDefinition Height="*" />
    </Grid.RowDefinitions>
    <DataGrid Grid.Row="0" Name="dg"/>
    <Button Grid.Row="1" Name="btn" Click="btn_Click" />

</Grid>

<强>代码隐藏

    List<SomeInfo> list = new List<SomeInfo>();

    public MainWindow()
    {
        InitializeComponent();
        list.Add(new SomeInfo() { Name = "PC", Description = "Computer", ID = 1 });
        list.Add(new SomeInfo() { Name = "PS", Description = "Playstation", ID = 2 });
        list.Add(new SomeInfo() { Name = "XB", Description = "Xbox", ID = 3 });
        this.dg.ItemsSource = list;
    }

    public class SomeInfo
    {
        public string Name { get; set; }
        public string Description { get; set; }
        public int ID { get; set; }
    }

    private void btn_Click(object sender, RoutedEventArgs e)
    {
        if (dg.SelectedIndex != -1)
        {
            DataGrid dataGrid = sender as DataGrid;
            DataGridRow row = (DataGridRow)dg.ItemContainerGenerator.ContainerFromIndex(dg.SelectedIndex);
            DataGridCell RowColumn = dg.Columns[0].GetCellContent(row).Parent as DataGridCell;
            btn.Content = ((TextBlock)RowColumn.Content).Text;
        }
    }

btn_click执行所有收集信息，其中最后2个使我的数据网格进行测试。

希望它会帮助你:)）

<强> ------------------编辑------------------------- -

从以下评论中您只需要

private void btn_Click(object sender, RoutedEventArgs e)
    {
        if (dg.SelectedIndex != -1)
        {
            DataGrid dataGrid = sender as DataGrid;
            DataGridRow row = (DataGridRow)dg.ItemContainerGenerator.ContainerFromIndex(dg.SelectedIndex);
            DataGridCell RowColumn = dg.Columns[0].GetCellContent(row).Parent as DataGridCell;
            btn.Content = ((TextBlock)RowColumn.Content).Text;
        }
    }

dg = your datagrid 
dg.Columns[0] = change 0 into what column you want
info from btn.Content = what you want the content to be

--------------编辑2 ------------ 要获得所选行的所有索引，只需

            int index = dg.SelectedIndex;
            btn.Content = index;

或者如果您不想存储整合

            btn.Content = dg.SelectedIndex;

在DataGrid中获取选定的行项目WPF不起作用

2 个答案: