Question

我有下表：

oDate       value1     value2     value3     value4
2014-06-01  10         20         30         40
2014-06-02  20         25         35         50

我想得到以下结果

oDate       oField     oValue
2014-06-01  Value1     10
2014-06-01  Value2     20
2014-06-01  Value3     30
2014-06-01  Value4     40

是否可以在SQL中执行此操作？需要建议。欢呼声，

Answer 1

你可以这样做：

测试数据：

DECLARE @tbl TABLE(oDate DATETIME,value1 INT,value2 INT,value3 INT,value4 INT)
INSERT INTO @tbl
VALUES
('2014-06-01',10,20,30,40),
('2014-06-02',20,25,35,50)

UNPIVOT查询

SELECT
    *
FROM
(
    SELECT
        oDate,
        value1,
        value2,
        value3,
        value4
    FROM
        @tbl
) sourceTable
UNPIVOT
(
    oField FOR oValue IN
    (value1,value2,value3,value4)
) AS unpvt

参考：

Using PIVOT and UNPIVOT

Answer 2

试试这个

SELECT DISTINCT ODATE,VALUE,FIELD
FROM 
   (SELECT odate,value1,value2,value3,value4
   FROM #temp) p
UNPIVOT
   (VALUE FOR FIELD IN 
      (value1,value2,value3,value4)
)AS unpvt;
GO

Answer 3

这个怎么样？

select
    oDate,
    'Value1' as oField,
    value1 as  oValue
from yourTable
union all
select
    oDate,
    'Value2' as oField,
    value2 as  oValue
from yourTable
union all
select
    oDate,
    'Value3' as oField,
    value3 as  oValue
from yourTable
union all
select
    oDate,
    'Value4' as oField,
    value4 as  oValue
from yourTable
order by oDate, oField

水平到垂直视图SQL

3 个答案: