Question

如何在字符串中查找图像标记并找到图像标记的src并替换为包含新src的数组。

array(
    [0] => YogurtParfait.png
    [1] => Smoothie_0.png
    [2] => Waffle.png
    [3] => EggSandwich_0.png
    [4] => BlueberryMuffins.png
)

这是我想用字符串src替换的数组。

$string = 'This is my test <img src="link_to_image1">, some other text
<img src="link_to_image1"> 
<img src="link_to_imag"> 
<img src="link_to_im"> 
<img src="link_to_imag">.

我希望得到像这样的出局

$string = 'This is my test 
<img src="YogurtParfait.png">,   
some other text<img src="Smoothie_0.png">
<img src="Waffle.png"> 
<img src="EggSandwich_0.png">
<img src="BlueberryMuffins.png">.

Answer 1

如果所有<img>标记确实具有相同的src属性，您可以迭代执行：

$links = array("YogurtParfait.png", ...);
$string = "This is my ...";
foreach ($links as $link) {
    $string = str_replace("link_to_image1", $link, $string);
}

如果它们实际上是link_to_image1，link_to_image2 ......那么：

$links = array("YogurtParfait.png", ...);
$string = "This is my ...";
foreach ($links as $k => $link) {
    $string = str_replace("link_to_image$k", $link, $string);
}

<强>更新

事实证明src是动态的，所以：

$links = array("YogurtParfait.png", ...);
$string = "This is my ...";

$startpos = strpos($string, '<img'); // position of first occurrence of <img
foreach ($links as $link) {
    $string =
        substr($string, 0, $startpos) // the part before the <img part
        . preg_replace(
             '/(<img src=")[^"]+(">)/',
             '\1' . $link . '\2',

             // the part from the actual <img part
             substr($string, $startpos) 
        );
    // get position of next <img part
    $startpos = strpos($string, '<img', $startpos + 1); 
}

Answer 2

让$array1成为包含数组的变量的名称。然后：

$array2 = array();
foreach($array1 as $i=>$src) 
    $array['link_to_image' . ($i + 1)] = $src;

$output = strtr($string, $array2);

image src替换为数组

2 个答案: