Question

我在这里试图做一些我觉得很容易的事情...... :-) 希望你们能帮助我。

这是为Linux Ubuntu编写的C函数......

我只需要显示一条确认消息，我希望用户按ENTER继续。

    #include <stdio.h>
    #include <time.h>

    void setDeposit(int account, int amount)
    {
        printf("You have successfully transfered %d EUR to the account number %d\nPlease press ENTER to continue\n", account, amount);
        getchar();

    }

应用程序＆＃34;忽略＆＃34; getchar（）并继续前进。

EDITED

包括评论中要求的整个程序：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "rbs-accmgr.c"
#include "rbs-graphics.c"
#include "rbs-struct.c"

//Main application function
int main()
{
    //Creating the application control instance
    application a = {1, 0, 0};

    //Populating the customer information with the login interface information
    customer c = {1234, "John", "Deer", 0};

    //Clearing the terminal window
    system("clear");

    //Keeps the application running as long as the user doesn't hit option 9 (Quit)
    while (a.status == 1)
    {
        //Displaying the graphic objects
        displayBanner();
        displayMenu();
        scanf("%d",&a.selectedOption);
        displayBanner();

        switch(a.selectedOption)
        {
            //Deposit
            case 1:
                printf("\nHow much would you like to deposit?\n");
                scanf("%d",&a.operationAmount);
                setDeposit(c.account, a.operationAmount);
                break;

            //Wrong option
            default:
                a.status = 0;
                break;
        }

        //Making sure all variables are zeroed
        a.operationAmount = 0;
    }

    return 0;

}

我在这里做错了什么？

谢谢！

Answer 1

请尝试以下方法告诉我。我认为您编写的getChar使用了scanf。阅读单独的while的{{1}}可以排除这种情况。我写了char以防你使用其他操作系统。

\r

有关此案例的详细信息，请参阅this thread。

按ENTER继续（Linux＆amp; C）

1 个答案: