Question

我有一个JSON数组对象，格式如下

{"Object1":[
    {"field1":"label1", "field2":"Name1"}, 
    {"field1":"label2", "field2":"Name2"},
    {"field1":"label3", "field2":"Name3"}
]}

我想将其转换为

{"label1":"Name1", "label2":"Name2", "label3":"Name3"}

我如何实现这一目标？

Answer 1

创建一个空对象，然后遍历Object1对象，对于其中的每个对象，将field1中的键添加到空数组中，其值为field2。

类似的东西：

var _obj = {};
jQuery.each(obj.Object1, function(k, v) {
    _obj[v.field1] = v.field2;
});

Answer 2

为实现这一目标这对你有用

//将此分配给任何变量

  var obj={"Object1":[
     {"field1":"label1", "field2":"Name1"}, 
    {"field1":"label2", "field2":"Name2"},
    {"field1":"label3", "field2":"Name3"}
]};
//Now take an array
try{
var arr=obj.Object1;
 var newObj={};

  for(var i=0;i<arr.length;i++)
  {
   newObj[arr[i].field1]=arr[i].field2;
  }

  alert(JSON.stringify(newObj));

}
 catch(err){alert(err.message);
}

Answer 3

使用基本for loop 的纯JS中的某些内容：http://jsfiddle.net/1c911ebr/

var object = {"Object1":[
    {"field1":"label1", "field2":"Name1"}, 
    {"field1":"label2", "field2":"Name2"},
    {"field1":"label3", "field2":"Name3"}
]},
    content = object["Object1"],
    newObj = {};


for(var i=0; i<content.length; i++){    
    newObj[content[i].field1] = content[i].field2;    
}

将返回：

{label1: "Name1", label2: "Name2", label3: "Name3"}

Answer 4

var json = {"Object1":[
    {"field1":"label1", "field2":"Name1"}, 
    {"field1":"label2", "field2":"Name2"},
    {"field1":"label3", "field2":"Name3"}
]};

function getJSONObj()
{
    var gList = eval("(" + json + ")");   
    var jsonObj = {};
    $.each(gList.Object1, function (keyData, valueData)
    {
        jsonObj[valueData.field1] = valueData.field2;
    });
}
getJSONObj();

输出：

{"label1":"Name1", "label2":"Name2", "label3":"Name3"}

Answer 5

尝试，基于纯JavaScript的解决方案。

 var gList= {"Object1":[
    {"field1":"label1", "field2":"Name1"}, 
    {"field1":"label2", "field2":"Name2"},
    {"field1":"label3", "field2":"Name3"}
]};

function transform(){
    var arr = [];

    for(var i=0;i<gList.Object1.length;i++){
        arr.push("'" + gList.Object1[i].field1 + "':'" + gList.Object1[i].field2 + "'");
    }
    alert(arr);
}

<强>输出

'label1':'Name1','label2':'Name2','label3':'Name3

DEMO

Answer 6

使用此代码。

var json = "{'Object1':["+
    "{'field1':'label1', 'field2':'Name1'},"+
    "{'field1':'label2', 'field2':'Name2'},"+
    "{'field1':'label3', 'field2':'Name3'}"+
"]}";


function getJSONObj(){
     var gList = eval("(" + json + ")");   
    var jsonObj = {};

    for(var i=0;i<gList.Object1.length;i++){
        jsonObj[gList.Object1[i].field1 ] = gList.Object1[i].field2;
    }
    alert(JSON.stringify(jsonObj));
}


getJSONObj();

链接 - http://jsfiddle.net/de5xoe3r/5/

在Javascript中将JSON数组对象解析为JSON对象

6 个答案: