我正在处理以下C ++作业问题:
"编写一个程序,让用户将12个月中每个月的总降雨量输入一系列双打。该计划应计算并显示当年的总降雨量,月平均降雨量以及最高和最低量的月份。
输入验证:不接受月降雨量数字的负数。"
我得到的错误是:
阅读这些内容,我想我可以安全地假设我的代码中有几个错误,即将双打整数转换成整数。我梳理了我的代码,寻找这些错误。我找到的那些int变量(根据Visual Studio 2012提供的行方向),我改为double;但它只会弄乱我的代码并产生更多错误。我甚至走出去,把每个int变量变成了一个双变量,只是被关于'计数器的20多个错误所打扰。变量;错误说"枚举类型。"
非常感谢这里的任何帮助,这项任务将于本周四下午(10月9日)到期。
这个程序确实编译了,但它也给了我各种垃圾答案和多余的垃圾答案。
到目前为止,这是我的代码:
#include<iostream>
#include<string>
using namespace std;
//Function prototypes
void totalAndAverage(int, double []);
void getHighest(int, double [], string []);
void getLowest(int, double [], string []);
//Global integer
const int SIZE = 12;
int main()
{
//Create arrays
double rainfallAmount[SIZE];
int index;
string months[SIZE] = { "January", "February", "March",
"April", "May", "June",
"July", "August", "September",
"October", "November", "December" };
//Get the amount of rain for each month
for ( index = 0; index < SIZE; index++)
{
cout << "Please enter the amount of rain (in inches) for month " << (index + 1) << ": " << endl; //+1 to not skip an array element
cin >> rainfallAmount[index];
//input validation, do not accept negative numbers
while (rainfallAmount[index] < 0)
{
cout << "You cannot have a negative amount of rainfall. Please enter the amount of rain." << endl;
cin >> rainfallAmount[index];
}
}
//Call function to find total and average
totalAndAverage(index, rainfallAmount);
//Call function to find highest
getHighest(index, rainfallAmount, months);
//Call function o find lowest
getLowest(index, rainfallAmount, months);
system("pause");
return 0;
}
void totalAndAverage(int i, double rainData[])
{
double total = 0, average;
//Find the total and average
for (i = 0; i < SIZE; i++)
{
total += rainData[i];
}
//Display total
cout << "The total rainfall is: " << total << endl;
//Find average and display
average = total / SIZE;
cout << "The average monthly rainfall is: " << average << endl;
}
void getHighest(int iCount, double rainData2[], string monthData[])
{
string highestMonth;
//Initialize highest
int highestRain = rainData2[0];
//Find the highest
for (iCount = 0; iCount < SIZE; iCount++)
{
if (rainData2[iCount] > highestRain)
{
highestRain = rainData2[iCount];
highestMonth = monthData[iCount];
//Display highest
cout << highestMonth << " had the most rainfall this year with " << highestRain << " inches." << endl;
}
}
}
void getLowest(int counter, double rainData3[], string monthDataCopy[])
{
string lowestMonth;
//Initialize highest
int lowestRain = rainData3[0];
//Find the highest
for (counter = 0; counter < SIZE; counter++)
{
if (rainData3[counter] > lowestRain)
{
lowestRain = rainData3[counter];
lowestMonth = monthDataCopy[counter];
//Display highest
cout << lowestMonth << " had the least rainfall this year with " << lowestRain << " inches." << endl;
}
}
}
答案 0 :(得分:1)
您写道:
int highestRain = rainData2[0];
int lowestRain = rainData3[0];
由于您希望找到最高和最低值而不会舍入为整数,因此您的&#34;最好到目前为止&#34;变量需要加倍。您可以明确地声明它们:
double highestRain = rainData2[0];
double lowestRain = rainData3[0];
您还可以使用auto
关键字。 (参见docs for Visual Studio 2012。)这种风格的优点和缺点超出了这个答案的范围,但你可能应该注意语言特性。
auto highestRain = rainData2[0];
auto lowestRain = rainData3[0];
答案 1 :(得分:1)
更改
int highestRain = rainData2[0];
要
double highestRain = rainData2[0];
同样的最低雨。
答案 2 :(得分:1)
首先,当你这样做时:
string months[SIZE] = { "January", "February", "March",
"April", "May", "June",
"July", "August", "September",
"October", "November", "December" };
您不需要“SIZE”,因此您可以将其更改为:
string months[] = { "January", "February", "March",
"April", "May", "June",
"July", "August", "September",
"October", "November", "December" };
C ++可以计算数组中有多少元素。
而不是说:
cout << "Please enter the amount of rain (in inches) for month " << (index + 1) << ": " << endl;
将(index+1)
替换为months[index]
。谁想读“1”而不是“1月”?
除此之外,你没有任何错误!这些是警告,因此它们不会使您的程序停止工作。
要取消警告,请替换:
//Initialize highest
int highestRain = rainData2[0];
使用:
//Initialize highest
double highestRain = rainData2[0];
同样的事情:
//Initialize highest
int lowestRain = rainData3[0];
将其更改为double
。这摆脱了警告但没有给你更多像你提到的错误。