Question

我们假设我的表格如下：

id | name | country
--------------------
   | John | USA
   | Mary | USA
   | Mike | USA

有人可以帮我一个可以为所有名字添加id的脚本吗？

由于

Answer 1

-- Create a temporary table for the example.
CREATE TABLE #People(Id int, Name nvarchar(10), Country nvarchar(10))

-- Insert data, leaving the Id column NULL.
INSERT INTO #People(Name, Country) SELECT
    'John', 'USA' UNION ALL SELECT
    'Mary', 'USA' UNION ALL SELECT
    'Mike', 'USA';

-- 1. Use Row_Number() to generate an Id.
-- 2. Wrap the query in a common table expression (CTE), which is like an inline view.
-- 3. If the CTE references a single table, we can update the CTE to affect the underlying table.
WITH PeopleCte AS (
    SELECT 
        Id, 
        Row_Number() OVER (ORDER BY (SELECT NULL)) AS NewId 
    FROM 
        #People    
)
UPDATE PeopleCte SET Id = NewId

SELECT * FROM #People

DROP TABLE #People

Answer 2

试试这个

update table set a.id=b.newid from  table a,(select row_number() over (order by (select null)) newid,name from #temp) b

根据需要进行更改

SQL - 将id添加到所有行

2 个答案: