Question

可能它看起来很简单，但它让我发疯。这是我的阵列：

$result =
Array

 (
   [0] => Array
        (
        [0] => 4
        [1] => 4
        [2] => 4
        [3] => 4
        [4] => 4
        [5] => 4
        [6] => 4
        [7] => 4
        [8] => 4
        [9] => 4
        [10] => 40
    )

[1] => Array
    (
        [0] => 5
        [1] => 4
        [2] => 4
        [3] => 4
        [4] => 4
        [5] => 4
        [6] => 4
        [7] => 4
        [8] => 4
        [9] => 4
        [10] => 41
    )

[2] => Array
    (
        [0] => 5
        [1] => 5
        [2] => 5
        [3] => 5
        [4] => 5
        [5] => 5
        [6] => 5
        [7] => 5
        [8] => 5
        [9] => 5
        [10] => 50
    )

）

这就是我想要转化为：

在array_merge之后

：

  $result =
 Array
(
[0] => 4
[1] => 4
[2] => 4
[3] => 4
[4] => 4
[5] => 4
[6] => 4
[7] => 4
[8] => 4
[9] => 4
[10] => 40
[11] => 5
[12] => 4
[13] => 4
[14] => 4
[15] => 4
[16] => 4
[17] => 4
[18] => 4
[19] => 4
[20] => 4
[21] => 41
[22] => 5
[23] => 5
[24] => 5
[25] => 5
[26] => 5
[27] => 5
[28] => 5
[29] => 5
[30] => 5
[31] => 5
[32] => 50
)

这是代码：

    <?php 
        $result = array(); 
    ?>
    @foreach ($detail_ratings as $detail_rating)
    <?php $result[] = json_decode($detail_rating); ?>

    @endforeach
    <?php 
    $result = array_merge($result[0],$result[1],$result[2]);
     ?>
    {{print_r($result)}}

如何在不手动使用此代码的情况下自动创建：

  $result = array_merge($result[0],$result[1],$result[2]);

这就是我已经做过的事情：

    foreach ($result as $key => $value) {
        $values[] =  array_merge($value,$result[$key]);
    }

Answer 1

也许这可以提供帮助： -

 function nameit(array $arr)
    {
        $newarr = array();
        foreach($arr as $a => $b)
        {
            $newarr[] = $b;
        }
        return $newarr;
    }

Answer 2

使用此

$result=array();
foreach($values as $value) {
    $result = array_merge($result,$value);
}

Answer 3

试试这个：

$final_array = array_merge($array1,$array2);

阵列合并失败

3 个答案: