Question

我正在尝试使用SAAJ为此WSDL调用SOAP Web服务。我在这里http://www.webservicex.net/ws/WSDetails.aspx?WSID=64提交了此WSDL的请求，它生成了以下SOAP请求..

<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
  <soap:Body>
    <GetGeoIP xmlns="http://www.webservicex.net/">
      <IPAddress>string</IPAddress>
    </GetGeoIP>
  </soap:Body>
</soap:Envelope>

使用SAAJ我生成了相同的SOAP请求并提交了它但得到了这个错误 - 服务器无法识别HTTP Header SOAPAction的值：。

<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><SOAP-ENV:Header/>
<SOAP-ENV:Body>
<GetGeoIP xmlns="http://www.webservicex.net/">
<IPAddress>SUNW</IPAddress>
</GetGeoIP>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>

Java代码：

package newpackage;

import javax.xml.namespace.QName;
import javax.xml.soap.*;

public class SOAPClientSAAJ {

    public static void main(String args[]) throws Exception {
        // Create SOAP Connection
        SOAPConnectionFactory soapConnectionFactory = SOAPConnectionFactory.newInstance();
        SOAPConnection soapConnection = soapConnectionFactory.createConnection();

        // Send SOAP Message to SOAP Server
        String url = "http://www.webservicex.net/geoipservice.asmx";
        SOAPMessage soapResponse = soapConnection.call(createSOAPRequest(), url);

        // print SOAP Response
        System.out.print("Response SOAP Message:");
        soapResponse.writeTo(System.out);

        soapConnection.close();
    }

    private static SOAPMessage createSOAPRequest() throws Exception {
        MessageFactory messageFactory = MessageFactory.newInstance();
        SOAPMessage soapMessage = messageFactory.createMessage();
        SOAPPart soapPart = soapMessage.getSOAPPart();

        String serverURI = "http://www.w3.org/2001/XMLSchema";

        // SOAP Envelope
        SOAPEnvelope envelope = soapPart.getEnvelope();
        envelope.addNamespaceDeclaration("xsd", serverURI);

        SOAPBody body = soapMessage.getSOAPBody();
        QName bodyName = new QName("http://www.webservicex.net/", "GetGeoIP" );
        SOAPBodyElement bodyElement = body.addBodyElement(bodyName);
        QName name = new QName("IPAddress");
        SOAPElement symbol = bodyElement.addChildElement(name);
        symbol.addTextNode("SUNW");
        soapMessage.saveChanges();

        /* Print the request message */
        System.out.print("Request SOAP Message:");
        soapMessage.writeTo(System.out);
        System.out.println();

        return soapMessage;
    }

}

Answer 1

添加

    MimeHeaders headers = soapMessage.getMimeHeaders();
    headers.addHeader("SOAPAction", "http://www.webservicex.net/" + "GetGeoIP");

Answer 2

如果您正在使用Marshelling和Unmarsheling，只需实现WebseviceMessageCallback接口，如：

public class SOAPConnector extends WebServiceGatewaySupport
{
    public Object callWebService( String url, Object request )
    {
        return getWebServiceTemplate().marshalSendAndReceive( url, request,  
webServiceMessage -> {
            (( SoapMessage )webServiceMessage).setSoapAction( 
"https://www.w3schools.com/xml/CelsiusToFahrenheit" );
        } );
    }
}

否则继续：https://stackoverflow.com/a/26253141/6097074

服务器无法识别HTTP标头SOAPAction的值：

2 个答案: