Question

你能给我一些指示（或指向谷歌搜索条件的正确方向）？在存储过程中，我有一个参数@TAG（字符串）。我收到了（＃14038314,14040071）＆＃39; （例如）来自另一个无法更改的应用程序。在存储过程中，我需要分开＆＃39;（14038314,14040071）＆＃39;在每个字符串值周围加上引号，重建它，去掉外部引号，去掉parens并将它传递给下面查询中的@TAG，以便它看起来像下面注释掉的那一行？

SELECT
    V.NAME AS VARIETY, TAGID
FROM 
    mfinv.dbo.onhand h
INNER JOIN 
    mfinv.dbo.onhand_tags t on h.onhand_id = t.onhand_id
INNER JOIN 
    mfinv.dbo.onhand_tag_details d on t.onhand_tag_id = d.onhand_tag_id
INNER JOIN 
    mfinv.dbo.FM_IC_PS_VARIETY V ON V.VARIETYIDX = d.VARIETYIDX
LEFT JOIN 
    mfinv.dbo.FM_IC_TAG TG ON TG.TAGIDX = t.TAGIDX
WHERE 
    h.onhand_id = (SELECT onhand_id FROM mfinv.dbo.onhand 
                   WHERE onhand_id = IDENT_CURRENT('mfinv.dbo.onhand'))
    AND TG.ID IN (@TAG)
   --AND TG.ID IN ('14038314','14040071')

Answer 1

您可以像这样使用动态SQL

DECLARE @TAG Nvarchar(MAX)='14038314,14040071'
set @TAG=''''+REPLACE(@TAG,',',''',''')+''''
--select @TAG

DECLARE @SQL NVARCHAR(MAX)=N'
Select V.NAME AS VARIETY, TAGID
FROM mfinv.dbo.onhand h
INNER JOIN mfinv.dbo.onhand_tags t on h.onhand_id = t.onhand_id
INNER JOIN mfinv.dbo.onhand_tag_details d on t.onhand_tag_id = d.onhand_tag_id
INNER JOIN mfinv.dbo.FM_IC_PS_VARIETY V ON V.VARIETYIDX = d.VARIETYIDX
LEFT JOIN mfinv.dbo.FM_IC_TAG TG ON TG.TAGIDX = t.TAGIDX
WHERE h.onhand_id = (SELECT onhand_id FROM mfinv.dbo.onhand 
WHERE onhand_id = IDENT_CURRENT   (''mfinv.dbo.onhand''))   
AND TG.ID IN ('+@TAG+')'

PRINT @SQL
EXEC (@SQL)

Answer 2

这就是我的所作所为。谢谢大家的回复。感谢dasblinkenlight回答“如何替换sql server中列的第一个和最后一个字符？”。感谢SQLMenace回答“如何在不创建函数的情况下在SQL Server中拆分分隔字符串？”。

以下是删除括号的方法：

@Tag nvarchar(256)
SET @Tag = SUBSTRING(@Tag, 2, LEN(@Tag)-2)

以下是我分割和重建@Tag的方法：

AND TG.ID in 
(

 SELECT SUBSTRING(',' + @Tag + ',', Number + 1,
  CHARINDEX(',', ',' + @Tag + ',', Number + 1) - Number -1)AS VALUE
  FROM master..spt_values
   WHERE Type = 'P'
   AND Number <= LEN(',' + @Tag + ',') - 1
  AND SUBSTRING(',' + @Tag + ',', Number, 1) = ','
)

SQL Server 2012 - 处理存储过程的字符串数据

2 个答案: