PHP类作为参数

Question

是否可以这样做？

class Foo
{
    public function __construct($bar)
    {
        $barish = new $bar();
        $barish->woo();
    }
}

class Bar
{
    function woo()
    {
        echo "wooooo";
        die();
    }
}

// Here the magic should happen
$foo = new Foo(Bar);

我希望wooooo但是我得到＆＃34;使用未定义的常量Bar＆＃34;。

Answer 1

您遗失''：

class Foo
{
    public function __construct($bar)
    {
        $barish = new $bar();
        $barish->woo();
    }
}

class Bar
{
    function woo()
    {
        echo "wooooo";
        die();
    }
}

// Here the magic should happen
$foo = new Foo('Bar');