Question

我想在服务器的handle函数内调用一个方法来执行它作为一个新线程。我想将请求作为参数传递，如下所示：

class serviceData(SocketServer.BaseRequestHandler):

    def handle(self):

        def dataTransfer(req):
            data = 'dummy'

            while len(data):              
                  #data = self.request.recv(1024)
                  data = req.recv(1024)
                  print str(data)

                  result = 'hi'


                  req.sendall(str(result))            

            print "Client exited"
            req.close()


        try:
            print "Client connected with ", self.client_address
            thread.start_new_thread( dataTransfer, (self.request, ) )
        except Exception, e:
            print e
            print "Error: unable to start thread"

我收到以下错误：

data = req.recv(1024)
File "usr/lib/python2.7/socket.py" line 170, in dummy
  raise error(EBADF, 'Bad file descriptor')
socket.error: [Errno 9] Bad file descriptor

任何人都知道我做得不好吗？

Answer 1

我找到了解决方案。将套接字服务器和线程与ThreadedTCPServer混合。所以：

class ThreadedTCPServer(SocketServer.ThreadingMixIn, SocketServer.TCPServer):
    pass

server = ThreadedTCPServer( ('', 1520), service )
server.serve_forever()

通过这种方式，def handle(self): ...... 为每个新连接创建一个新线程。

坏文件描述符python服务器

1 个答案: