Question

我的查询是这样的：

SELECT order_number,dr_amount FROM data WHERE order_number IN (select order_number from data where dr_machine='KBA R-' && dr_code='Tryckning' && dr_amount IS NOT NULL && dr_amount!=0 group by order_number having count(*)<2) && dr_machine='KBA R-' && dr_code='Tryckning' && dr_date>='1381442400' && id>'397433' && order_number!='16952' ORDER BY id limit 1;

结果如下：

+--------------+-----------+
| order_number | dr_amount |
+--------------+-----------+
|        17047 | 1307      |
+--------------+-----------+

这是我想进一步处理的结果。现在我想为此添加一个子查询。我需要在DATA WHERE oi_amount＆gt; 0中检查order_number（17047）。所以我尝试对此进行查询：

SELECT order_number,dr_amount FROM data WHERE order_number IN (select order_number from data where dr_machine='KBA R-' && dr_code='Tryckning' && dr_amount IS NOT NULL && dr_amount!=0 group by order_number having count(*)<2) && dr_machine='KBA R-' && dr_code='Tryckning' && dr_date>='1381442400' && id>'397433' && order_number!='16952' && order_number in (select order_number from data where oi_amount>0) ORDER BY id limit 1;

但这给了我：

+--------------+-----------+
| order_number | dr_amount |
+--------------+-----------+
|        17046 | 653       |
+--------------+-----------+

这不是我想要的。我想从该查询中返回无结果，因为order_number 17047具有oi_amount＆lt; = 0（或NULL）我知道当order_number 17047不匹配时，它会跳到匹配的下一行，这就是order_number为17046的行。所以我想在LIMIT 1中添加一个子查询。像这样：

SELECT order_number,dr_amount FROM data WHERE order_number IN (select order_number from data where dr_machine='KBA R-' && dr_code='Tryckning' && dr_amount IS NOT NULL && dr_amount!=0 group by order_number having count(*)<2) && order_number in (select order_number from data where dr_machine='KBA R-' && dr_code='Tryckning' && dr_date>='1381442400' && id>'397433' && order_number!='16952' ORDER BY id limit 1);

但是这会引发错误：

This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery'

我的表格如下：

+--------+--------------+-------------+------------+------------+-----------+-----------+
| id     | order_number | dr_worker   | dr_code    | dr_machine | dr_amount | oi_amount |
+--------+--------------+-------------+------------+------------+-----------+-----------+
| 332144 |        16952 | NULL        | NULL       | NULL       | NULL      | 2000      |
| 397432 |        16952 | Gustafsson, | Intag      | KBA R-     | 1         | NULL      |
| 397433 |        16952 | Gustafsson, | Tryckning  | KBA R-     | 1307      | NULL      |
| 397434 |        17047 | Gustafsson, | Intag      | KBA R-     | 1         | NULL      |
| 397435 |        17047 | Gustafsson, | Tryckning  | KBA R-     | 1307      | NULL      |
+--------+--------------+-------------+------------+------------+-----------+-----------+

正如你所看到的，order_number 17047没有oi_amount记录，这就是为什么我不想返回结果/空结果。

我对如何使用JOIN知之甚少，但也许这就是要走的路？我已经尝试过som查询，但我不确定这是否会起作用（我所有的JOIN查询都有一些语法错误，所以我放弃了）

祝你好运尼克拉斯

Answer 1

尝试使用join代替：

SELECT order_number, dr_amount
FROM data d join
     (select order_number
      from data
      where dr_machine = 'KBA R-' and
            dr_code = 'Tryckning' and
            dr_amount IS NOT NULL and
            dr_amount <> 0
      group by order_number
      having count(*) < 2
     ) i
     on d.order_number = i.order_number
WHERE d.dr_machine = 'KBA R-' and
      d.dr_code = 'Tryckning' and
      d.dr_date >= '1381442400' and
      d.id > '397433' and
      d.order_number <> '16952'
ORDER BY id
limit 1;

请注意，我更改了您的运算符以符合SQL标准：<>而不是!=和and而不是&&。此外，如果看起来像数字的常数确实是数字，那么您就不需要单引号。

mysql - 想在IN子查询中使用LIMIT，如何解决？

1 个答案: