Question

我必须点击鼠标悬停后生成的图块。我在下面编写了代码，但它仍然无效。

WebElement FrontElement=driver.findElement(By.xpath("//a[@class='sol-itm-bx relative front-app-nm']/span[text()='UI Auto Test12345']"));
WebElement BackElement= driver.findElement(By.xpath("//a[@class='relative back-app-desc']/span[text()='UI Auto Test12345']"));
Actions builder = new Actions(driver);

builder.moveToElement(FrontElement);
builder.perform();
builder.clickAndHold(FrontElement);
BackElement.click();

Answer 1

要使用Actions()类，您需要将操作链接在一起。单独的命令将无法以您希望的方式工作。

Actions builder = new Actions(driver);
builder.moveToElement(driver.findElement(By.xpath("//a[@class='sol-itm-bx relative front-app-nm']/span[text()='UI Auto Test12345']")))
     .moveToElement(driver.findElement(By.xpath("//a[@class='relative back-app-desc']/span[text()='UI Auto Test12345']")))
     .click().perform();

注意：为了便于阅读，我将线条分开了。编辑：'build'到'builder'NullPointerException

单击鼠标悬停后可见的元素

1 个答案: