Question

我有当前的代码，我试图用***来掩盖部分用户的电子邮件

$user_email                         = info@test.com

$unmasked_user_email_array          = explode('@', $user_email);
$unmasked_user_email_string         = $unmasked_user_email[0];
$unmasked_user_email_string_length  = strlen($unmasked_user_email_string);

if ($unmasked_user_email_string_length > 4) {
    replace the last three characters of $unmasked_user_email_string with ***
}   
else if ($unmasked_user_email_string_length < 5) {
    replace the last two characters of $unmasked_user_email_string with **
}
else if ($unmasked_user_email_string_length < 4) {
    replace the last one character of $unmasked_user_email_string with *
}

我的问题是，我应该使用哪些方法或功能来完成我想要做的事情？

由于

Answer 1

使用php的substr方法。

Syntax : substr($string,$start,$length);

and substr($string,$start); to get the entire string after the "$start" position(staring from 0)

请参阅：http://in1.php.net/substr

所以，

if ($unmasked_user_email_string_length > 4) {

$unmasked_user_email_string with = substr($unmasked_user_email_string,0,strlen($unmasked_user_email_string)-3);
//abc@xzy.com => abc@xyz.***

}   

else if ($unmasked_user_email_string_length < 5) {
//do it yourself

}

else if ($unmasked_user_email_string_length < 4) {
//do it yourself

}

Answer 2

这将为您解决问题。使用php native function substr（）删除最后几个字符。然后我们在为隐藏元素添加一些星星后重建电子邮件地址。另外，你的$ unmasked_user_email [0]应该是$ unmaskd_user_email_array [0]：

$user_email                         = "info@test.com"

$unmasked_user_email_array          = explode('@', $user_email);
$unmasked_user_email_string         = $unmasked_user_email_array[0];
$unmasked_user_email_string_length  = strlen($unmasked_user_email_string);

if ($unmasked_user_email_string_length > 4) {
    $email = substr( $unmasked_user_email_string, 0, -4 ) . '****' . $unmasked_user_email_array[1];
}   
else if ($unmasked_user_email_string_length < 5) {
    $email = substr( $unmasked_user_email_string, 0, -2 ) . '**' . $unmasked_user_email_array[1];
}
else if ($unmasked_user_email_string_length < 4) {
    $email = substr( $unmasked_user_email_string, 0, -1 ) . '*' . $unmasked_user_email_array[1];
}

Php substr（）手册：http://php.net/manual/en/function.substr.php

Answer 3

您可以使用substr（php.net/substr）来剪切字符串的结尾，然后连接您想要的*。例如：

$user_email_hidden = substr($unmasked_user_email_string, 0, $unmasked_user_email_string_length-4) . '****'

Answer 4

<?php
$user_email                         = "o1231@test.com";

$unmasked_user_email_array          = explode("@", $user_email);
$unmasked_user_email_string         = $unmasked_user_email_array[0];
$unmasked_user_email_string_length  = strlen($unmasked_user_email_string);

if ($unmasked_user_email_string_length > 4) {
    // replace the last three characters of $unmasked_user_email_string with ***
    $unmasked_user_email_string = substr($unmasked_user_email_string, 0, -3) . '***'; 
}   
else if ($unmasked_user_email_string_length == 5) {
    // replace the last two characters of $unmasked_user_email_string with **
    $unmasked_user_email_string = substr($unmasked_user_email_string, 0, -2) . '**'; 
}
else if (($unmasked_user_email_string_length < 4) && ($unmasked_user_email_string_length >= 2)) {
    // replace the last one character of $unmasked_user_email_string with *
    $unmasked_user_email_string = substr($unmasked_user_email_string, 0, -1) . '*'; 
}
else {
    // replace the last one character of $unmasked_user_email_string with *
    $unmasked_user_email_string = substr($unmasked_user_email_string, 0, -1) . '*****'; 
}
echo $unmasked_user_email_string;

?>

PHP替换字符串中的特定数量的字符

4 个答案: