Question

我如何联合list<String>中的单词以便将其真实形式作为句子回复

String sentence = "i get money. i love it. i want to buy. something. ";
String[] arrSent = sentence.split("\\. ");

for(int i=0; i<arrSent.length; i++) {
    String[] words = arrSent[i].split("\\ ");
    for(int j=0; j<words.length; j++ {
        listWord.add(words[j]);
    }
}

，输出为：

i
get
money
i
love
it
i
want
to
buy
something

我只是想将它重建为真实形式（作为句子）

更新!!!

我试过像你建议的那样。但我发现了一种新的困难方式。

我从列表中删除了一个单词“love”，然后我添加到新列表“listWord2”。当我将它重建为真实形式作为句子时，新句子中的.消失

这是代码：

String [] arrays2 = listKata2.toArray(new String[listWord2.size()]);
sentence = Arrays.deepToString(arrays2).replaceAll(",", "");
System.out.println("result :  : "+sentence);

，输出是：

[i get money i it i want to buy something]

缺少.

我应该再将listWord2空格分开吗？请建议我

Answer 1

唯一真正的答案是，一旦你拿走了所有的单词并且在句子之间失去了完整的句号，就无法将它们带回来 - 信息永远丢失，因此无法重建原始结构。 / p>

您需要弄清楚如何（实际上 if ）要保留该信息。一种方法是保留你的句子数组，只用字列表而不是句子字符串填充它，如下所示：

List<List<String>> sentences = new List<List<String>>();
String[] arrSent = sentence.split("\\. ");
for (int i = 0; i < arrSent.length; i++)
    sentences.add(Arrays.asList(arrSend[i].split("\\ "));

然后你会得到像

这样的东西

(
   ( "i", "get", "money" ),
   ( "i", "love", "it" ),
   ( "i", "want", "to", "buy" ),
   ( "something" )
)

很容易看出如何从中重建原始文本。

另一种选择可能是保留扁平的单词列表，但为句子终止的位置添加特殊的占位符 - 例如使用null值。扫描单词的算法应该知道如何处理这些占位符而不会崩溃，而重建句子的算法将使用那些来添加句号：

String[] arrSent = sentence.split("\\. ");

for(int i=0; i<arrSent.length; i++) {
    String[] words = arrSent[i].split("\\ ");
    for(int j=0; j<words.length; j++ {
        listWord.add(words[j]);
    }
    listWord.add(null);
}

// Rebuild
StringBuffer output = new StringBuffer();
for (Iterator<String> it = listWord.iterator(); it.hasNext(); ) {
     String val = it.next();
     String nextword = (output.length() > 0 ? " " : "") + val;
     output.append(val == null ? "." : nextword);
}

Answer 2

尝试以下：

String sentence = "i get money. i love it. i want to buy. something. ";
String[] arrSent = sentence.split(" ");
sentence=Arrays.toString(arrSent).replaceAll(",", "");
System.out.println(sentence);

输出

[i get money. i love it. i want to buy. something.]

如果你想在句子中.，则下面没有.。

String sentence = "i get money. i love it. i want to buy. something. ";
String[] arrSent = sentence.split("\\. ");
sentence=Arrays.toString(arrSent).replaceAll(",", "");
System.out.println(sentence);

输出

[i get money i love it i want to buy something]

Answer 3

执行：

String sentence = "i get money. i love it. i want to buy. something. ";
String[] arrSent = sentence.split("\\. ");

String sentenceRebuild = "";
for(int i=0; i<arrSent.length; i++){
  String[] words = arrSent[i].split("\\ ");

  for(int j=0; j<words.length; j++){
    sentenceRebuild += words[j];
  }
}

从String-Array java中的标记/单词构建一个句子

3 个答案: