Question

#include<stdio.h>
int main()
{

int choice;
printf("Enter 1 for Programmers Name and ID\n");
printf("Enter 2 to Perform Integer Operation\n");
printf("Enter 3 to Perform Floating Point Operation\n");
scanf("%d", &choice);
system("CLS");

if (choice == 1)
    printf("Connor \n000000000\n");

else if (choice == 2)
{
    char c;
    int num1, num2;
    printf("Enter operator:");
    scanf("%c", &c);
    getchar();
    printf("Enter two integer's :");
    scanf("%d %d", &num1, &num2);

    switch (c)
    {
    case '+':
        printf("%d + %d = %d", num1, num2, num1 + num2);
        break;
    case '-':
        printf("%d - %d = %d", num1, num2, num1 - num2);
        break;
    case '*':
        printf("%d * %d = %d", num1, num2, num1*num2);
        break;
    case '/':
        printf("%d / %d = %d", num1, num2, num1 / num2);
        break;

    default:
        printf("The value of c = '%c'\n");
        system("pause");
        return(0);
    }
}
else if (choice == 3)
    printf("Enter two \n");


system("pause");
return(0);
}

我需要一些帮助来解决这个代码的操作部分的一个小问题.......一切正常，因为可以放入运算符和整数但我没有得到交换机的输出

Answer 1

这绝对有用

    #include<stdio.h>
int main()
{

int choice;
printf("Enter 1 for Programmers Name and ID\n");
printf("Enter 2 to Perform Integer Operation\n");
printf("Enter 3 to Perform Floating Point Operation\n");
scanf("%d", &choice);
getchar();
if (choice == 1)

    printf("Connor \n000000000\n");


else if (choice == 2)


{
    char c;
    int num1, num2;
    printf("Enter operator:");
    scanf("%c", &c);
    printf("Enter two integer's :");
    scanf("%d %d", &num1, &num2);
    switch (c)
    {

    case '+':
        printf("%d + %d = %d", num1, num2, num1 + num2);
        break;
    case '-':
        printf("%d - %d = %d", num1, num2, num1 - num2);
        break;
    case '*':
        printf("%d * %d = %d", num1, num2, num1*num2);
        break;
    case '/':
        printf("%d / %d = %d", num1, num2, num1 / num2);
        break;

    default:
        printf("The value of c = '%c'\n" , c);
        return(0);
    }

}
else if (choice == 3)
    printf("Enter two \n");

}

Answer 2

变化：

scanf("%c", &c);
getchar();

为：

scanf(" %c", &c);

为每个人添加\n：

printf("%d + %d = %d\n", num1, num2, num1 + num2);
                    ^^

当您告诉char打印一个时，实际提供printf()：

printf("The value of c = '%c'\n", c);
                                ^^^

它应该适合你。修改后的代码，删除了所有system()废话：

#include <stdio.h>

int main(void)
{
    int choice;

    printf("Enter 1 for Programmers Name and ID\n");
    printf("Enter 2 to Perform Integer Operation\n");
    printf("Enter 3 to Perform Floating Point Operation\n");
    scanf("%d", &choice);

    if ( choice == 1 ) {
        printf("Connor \n000000000\n");
    }
    else if ( choice == 2 ) {
        char c;
        int num1, num2;

        printf("Enter operator:");
        scanf(" %c", &c);

        printf("Enter two integers :");
        scanf("%d %d", &num1, &num2);

        switch ( c ) {

        case '+':
            printf("%d + %d = %d\n", num1, num2, num1 + num2);
            break;
        case '-':
            printf("%d - %d = %d\n", num1, num2, num1 - num2);
            break;
        case '*':
            printf("%d * %d = %d\n", num1, num2, num1 * num2);
            break;
        case '/':
            printf("%d / %d = %d\n", num1, num2, num1 / num2);
            break;
        default:
            printf("The value of c = '%c'\n", c);
            break;
        }
    } else if ( choice == 3 ) {
        printf("Enter two \n");
    }
    else {
        printf("Invalid choice.\n");
    }

    return 0;
}

带样本输出：

paul@thoth:~/src/sandbox$ ./cal
Enter 1 for Programmers Name and ID
Enter 2 to Perform Integer Operation
Enter 3 to Perform Floating Point Operation
2
Enter operator:*
Enter two integers :4 6
4 * 6 = 24
paul@thoth:~/src/sandbox$

Switch case程序不提供输出

2 个答案: