我是Json的新手并试图了解如何使用Json.Net解析它。我试图为我的json输入创建对象,但是我被卡住了。我不太确定如何解析输入,所以我可以迭代它并输出季节编号和剧集名称。
任何可以指引我朝正确方向前进的人?
JSON:
{
"data":{
"1921":{
"1":{
"airdate":"1921-03-20",
"name":"Cleaning Up!!?",
"quality":"N/A",
"status":"Wanted"
},
"2":{
"airdate":"1921-03-20",
"name":"Kansas City Girls Are Rolling Their Own Now",
"quality":"N/A",
"status":"Wanted"
},
"3":{
"airdate":"1921-03-20",
"name":"Did You Ever Take a Ride Over Kansas City Street 'in a Fliver'",
"quality":"N/A",
"status":"Wanted"
},
"4":{
"airdate":"1921-03-20",
"name":"Kansas City's Spring Clean-Up",
"quality":"N/A",
"status":"Wanted"
}
},
"1923":{
"1":{
"airdate":"2013-05-16",
"name":"Alice's Wonderland - aka - Alice in Slumberland",
"quality":"Unknown",
"status":"Downloaded"
}
}
},
"message":"",
"result":"success"
}
代码:
static void Main(string[] args)
{
RootObject data = JsonConvert.DeserializeObject<RootObject>(System.IO.File.ReadAllText(@"C:\Users\Benjamin\Desktop\json\input.txt"));
foreach (var e in data)
{
// Being able to output Season and Episode name like:
// 1921 - Cleaning Up!!?
}
}
public class RootObject
{
public Dictionary<int, Season> data { get; set; }
public string message { get; set; }
public string result { get; set; }
}
public class Season
{
public Dictionary<string, Episode> number { get; set; }
}
public class Episode
{
public string airdate { get; set; }
public string name { get; set; }
public string quality { get; set; }
public string status { get; set; }
}
答案 0 :(得分:2)
更改RootObject
:
public class RootObject
{
public Dictionary<int, Dictionary<string, Episode>> data { get; set; }
public string message { get; set; }
public string result { get; set; }
}
然后你可以这样做:
RootObject root = JsonConvert.DeserializeObject<RootObject>(data);
foreach (var s in root.data)
{
foreach (var e in s.Value)
{
Console.WriteLine(string.Format("{0} - {1}", s.Key, e.Value.name));
// access whatever properties you want here...
}
}
注意,我们已经删除了Season
对象,因为JSON.net将无法映射到属性number
,因为它不是原始JSON中的属性(您可以使其工作,但它需要一些摆弄自定义序列化。)
如果真的想要一个LINQ解决方案,那么就像:
root.data.ToList().ForEach(s =>
{
s.Value.ToList().ForEach(e =>
{
Console.WriteLine(string.Format("{0} - {1}", s.Key, e.Value.name));
});
});
实现同样的目标,但需要将字典复制到列表中,如果字典非常大,可能会出现问题。