Question

我在java中使用以下函数连接到服务器中的php脚本。该脚本查询图像（BLOB），对其进行编码（base64）并以JSON格式将其发回。

问题是我可以获得一些编码数据但不是全部。我应该在httpRequest上使用任何标头吗？我做错了什么？

这是我的java函数：

 public JSONObject makeHttpRequest(String url, String method,
        List<NameValuePair> params) {

    // Making HTTP request
    try {
            // request method is POST
            // defaultHttpClient
            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost(url);
            httpPost.setEntity(new UrlEncodedFormEntity(params));

            HttpResponse httpResponse = httpClient.execute(httpPost);
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();          

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

    try {
        BufferedReader reader = new BufferedReader(
                new InputStreamReader(is, "UTF-8"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        is.close();
        json = sb.toString();
        System.out.println("Print1: "+json);
    } catch (Exception e) {
        Log.e("Buffer Error", "Error converting result " + e.toString());
        return null;
    }

    // try parse the string to a JSON object
    try {
        jObj = new JSONObject(json);
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
        return null;
    }
    System.out.println("Print2: "+jObj.toString());
    // return JSON String
    return jObj;

}

这是我的PHP代码，显示了JSON结构：

$response = array(
"success" => 0,
"message" => "",
"data" => "");


$stmt->bindColumn(1, $binary, PDO::PARAM_LOB);
$stmt->bindColumn(2, $professorName);
$stmt->fetch(PDO::FETCH_BOUND);

$pic = base64_encode($binary);

$data = array(
    "photo" => $pic,
    "professorName" => $professorName
    );

$response["success"] = 1;
$response["message"] = "We have results!";
$response["data"] = $data;
echo json_encode($response);

经过测试，我意识到如果我使用一个小图像（测试尺寸<1Kb），一切都会正常工作。

如果我尝试获得更大的图像（此处为5 Kb），我获得的数据将在中间切割。 json结构没有完成。

以下是成功转移的示例：

Print1: {"success":1,"message":"We have results!","data":
{"photo":"iVBORw0KGgoAAAANS~~~~more data~~~~N6GGYzAAAAAElFTkSuQmCC","professorName":"cluvas"}}

Print2: {"data":{"kathigitisName":"cluvas","photo":"iVBORw0K~~~~more data~~~~AElFTkSuQmCC"},
"message":"We have results!","success":1}

这是一个不成功的例子

Print1: {"success":1,"message":"We have results!","data":
{"photo":"\/9j\/4AAQS~~~~more data~~~~6KKogkH\/  //unexpected end of data

Print2: {"data":{"professorName":"cluvas",
"photo":"\/9j\/4AAQS~~~~more data~~~~K+U\/Ce    //unexpected end of data

POST httpRequest不会获取所有数据

0 个答案: