Question

编写一个Python程序，重复要求用户输入硬币值，直到总金额与目标价值相匹配。目标值是随机的生成1到99之间的整数（含）。

例如，对于目标值31，用户输入的硬币值可以是25,5和1因为31 = 25 + 5 + 1。

为了在Python中为目标值生成随机数，您必须这样做在程序开头写下以下语句：

import random

然后，您可以在程序中编写以下语句以生成随机语句号码：

rand = random.randint(1, 99)

上述语句将生成1到99之间的随机数（两者都是终点是包容性的）。该随机数将存储在变量rand中（根据上述声明）。如果需要，您可以使用其他变量名称。存储在名为rand的变量中的随机值是目标硬币值用户必须输入硬币。

程序的示例运行

在下一页是程序的完整示例运行。这是个程序如何表现的例子;在下文中，59,70和76 是随机生成的数字。

实施例：此练习的目的是输入多个硬币值加起来显示的目标值。

输入1-penny，5-nickel，10-dime和25-quarter的硬币值。在最后输入的硬币值后点击返回。

Enter coins that add up to 59 cents, one per line. 
Enter first coin: 
Enter first coin: 3 
Invalid entry 
Enter first coin: 25 
Enter next coin: 5 
Enter next coin: 25 
Enter next coin: 2 
Invalid entry 
Enter next coin: 1 
Enter next coin: 1 
Enter next coin: 1 
Enter next coin: 1 
Enter next coin: 
Correct! 
Try again (y/n)?: y 
Enter coins that add up to 70 cents, one per line. 
Enter first coin: 2 
Invalid entry 
Enter first coin: 25 
Enter next coin: 25 
Enter next coin: 10 
Enter next coin: 5 
Enter next coin: 1 
Enter next coin: 25 
Sorry - total amount exceeds 70 cents. 
Try again (y/n)?: y 
Enter coins that add up to 76 cents, one per line. 
Enter first coin: 25 
Enter next coin: 25 
Enter next coin: 1 
Enter next coin: 25 
Enter next coin: 
Correct! 
Try again (y/n)?: n 
Thanks for playing ... goodbye

这是我到目前为止的代码：

import random

def chkcoin(acoin):
    basecoin = ["1"," 5", "10", "25"]
    flag = False
    for bc in basecoin:
        if acoin == int(bc):
            return True
        else:
            flag = True
    if flag:
        print('Invalid entry')
        return False

def tryAgain():
    comd = input('Try again (y/n)?: ')
    if comd == 'y':
        return True
    elif comd == 'n':
        print ('Thanks for playing ... goodbye')
        return False
    else:
        print ('Command error! Please enter y or n.')
        print ('Thanks for playing ... goodbye')
        return False

导入随机

def chkcoin(acoin): basecoin = ["1"," 5", "10", "25"] flag = False for bc in basecoin: if acoin == int(bc): return True else: flag = True if flag: print('Invalid entry') return False def tryAgain(): comd = input('Try again (y/n)?: ') if comd == 'y': return True elif comd == 'n': print ('Thanks for playing ... goodbye') return False else: print ('Command error! Please enter y or n.') print ('Thanks for playing ... goodbye') return False

有人能帮助我吗？我有2个问题需要解决。

当我需要输入号码时。如果我输入空格键。这个程序会崩溃。我想如果我输入空格键，结果将像8或其他。＆＃34;无效的尝试＆＃34;
这个python会在一场比赛后崩溃。怎么解决？我在python2中编写这个python。突然间，我发现我需要在python3中编写。但我不知道如何改变它。 TY

Answer 1

您想要查看while循环

例如：

# Set the target value
target = 50
# Initialize the running total to 0
total = 0
run the indented code while target != total
while total != target:
    # ask the user for a number
    choice = input("Number? ")
    # add choice to total
    total += choice

以上while会在total != 50评估为True的情况下继续运行。

Answer 2

import random
def amountGame():
   coin=[25,5,1]
   target=random.randint(1,99)
   print(f'Your Amount is {target}')
   total=0
   while target!=total:
       x=int(input('Enter pic of amount :'))
       if x in coin and (target-total)>=x:
           total+=x
       else:
           print('Envalid Entry')
   print('You Solve problam')


opt=''
while opt!='N':
    amountGame()
    opt=input('Do you want to continue press Y else N :).upper()

编写一个Python程序，重复要求用户输入硬币值，直到总金额与目标值匹配

2 个答案: