我试图获得最小值的start和最大值的end outoff下面的对象。该对象是sql脚本的结果。
object(CI_DB_mysql_result)[18]
public 'conn_id' => resource(54, mysql link persistent)
public 'result_id' => resource(61, mysql result)
public 'result_array' =>
array (size=0)
empty
public 'result_object' =>
array (size=3)
0 =>
object(stdClass)[16]
public 'id' => string '601' (length=3)
public 'scheduled' => string '0' (length=1)
public 'start' => string '2014-10-17 06:00:00' (length=19)
public 'end' => string '2014-10-17 11:00:00' (length=19)
1 =>
object(stdClass)[19]
public 'id' => string '602' (length=3)
public 'scheduled' => string '0' (length=1)
public 'start' => string '2014-10-17 18:00:00' (length=19)
public 'end' => string '2014-10-17 19:30:00' (length=19)
2 =>
object(stdClass)[20]
public 'id' => string '603' (length=3)
public 'scheduled' => string '1' (length=1)
public 'start' => string '2014-10-17 11:00:00' (length=19)
public 'end' => string '2014-10-17 18:00:00' (length=19)
public 'custom_result_object' =>
array (size=0)
empty
public 'current_row' => int 0
public 'num_rows' => int 3
public 'row_data' => null
在这种情况下,start =' 2014-10-17 06:00:00'最终的价值= 2014-10-17 19:30:00'所以我正在寻找的结果如下:
$smallest_start_value = '2014-10-17 06:00:00';
$biggest_end_value = '2014-10-17 19:30:00';
为了计算这个结果,代码应该如何?
功能:
function unschedule_resource() {
$event_id = 4;//$_POST['event_id'];
$event_start = '2014-10-17 11:00:00';//$_POST['event_start'];
$event_end = '2014-10-17 18:00:00';//$_POST['event_end'];
// Get resource id
$this->db->select('
event.resource_id'
);
$this->db->from('promo_manager.event');
$this->db->where('event.id =', $event_id);
$data = $this->db->get();
foreach ($data->result() as $row) {
echo $row->resource_id . "<br>";
$resource_id = $row->resource_id;
}
// Get resource events to unschedule
$this->db->select('
resource_calendar.id,
resource_calendar.scheduled,
resource_calendar.start,
resource_calendar.end'
);
$this->db->from('promo_manager.resource_calendar');
$this->db->where('resource_calendar.resource_id =', $resource_id);
$this->db->where('resource_calendar.start =', $event_start);
$this->db->where('resource_calendar.end =', $event_end);
$this->db->or_where('resource_calendar.end =', $event_start);
$this->db->or_where('resource_calendar.start =', $event_end);
$data = $this->db->get();
$lowest_value = null;
$highest_value = null;
foreach ($data as $the_key => $the_value) {
if ($the_key == 'start') {
if ($lowest_value === null) {
$lowest_value = $the_value;
}
if ($the_value < $lowest_value) {
$lowest_value = $the_value;
}
}
}
//echo $lowest_value;
var_dump ($lowest_value) ;
}
答案 0 :(得分:0)
Sam的代码应如下所示:
$lowest_value = null;
$highest_value = null;
foreach($data as $obj) { //$data should be the array containing the result objects.
$start = $obj->start;
$end = $obj->end;
if ($lowest_value === null)
$lowest_value = $start;
else
if ($lowest_value > $start)
$lowest_value = $start;
if ($highest_value === null)
$highest_value = $end;
else
if ($highest_value < $end)
$highest_value = $end;
}
可缩短为:
if ($lowest_value === null || $lowest_value > $start)
$lowest_value = $start;
if ($highest_value === null || $highest_value < $end)
$highest_value = $end;
两个值都可以在一次迭代中生成而没有问题。请注意,<
和>
适用于您将日期格式化为给定的情况。另外,您需要使用日期功能来比较日期。
您还可以使用MySQL使用聚合方法Min或Max直接查询Min / Max值:http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html
(如果您不需要加载每个对象,这将更快)
答案 1 :(得分:-1)
我不确定在选择声明中你是否有办法做到这一点,我不会这样做。将结果对象放入数组中。这是超级基础,但应该完成工作。
$lowest_value = null;
$highest_value = null;
foreach(result_object as $the_key => $the_value) {
if($the_key == 'start') {
if($lowest_value === null) {
$lowest_value = $the_value;
}
if(the_value < $lowest_value) {
$lowest_value = $the_value;
}
}
}
$lowest_value = null;
$highest_value = null;
foreach(result_object as $the_key => $the_value) {
if($the_key == 'start') {
if($lowest_value === null) {
$lowest_value = $the_value;
}
if(the_value < $lowest_value) {
$lowest_value = $the_value;
}
}
}
只需更改操作符
再次检查结束值