如何在C程序中使用gnuplot来绘制图形

Question

我试图在C程序中绘制图表（Windows 7） 我维护了一个图形点数组，比如x []和y1 []，y2 []和y3 []。我想为固定的x点绘制多个y点。 如何在我的程序中使用gnuplot绘制图形？

Answer 1

不是最优雅的解决方案，但这应该有效：

int main(int argc, char **argv){
    FILE * temp = fopen("data.temp", "w");
    FILE * gnuplotPipe = popen ("gnuplot -persistent", "w");
    for(Iterate over your array so that you create another exact temporal array){

        float a, b, c;

        x = something;
        y1 = something;
        y2 = something;
        y3 = something;

        fprintf(temp, "%d %d %d %d \n", x, y1, y2, y3);
    }

    fprintf(gnuplotPipe, "(here whatever you want to tell gnuplot to do) i.e plot 'data.temp' using 1:2 with lines, etc");    

    return 0;
}

或者你可以这样做：

int plot(){
    system("gnuplot -p -e \"(Here put whatever you would put in gnuplot as if you were ploting manually)\"");
    return 0;
}