Question

我是SQL世界的新手，有人可以帮我解决这个问题。

我有两个具有相同列的表，CID，Amount。两者都有关于如何插入数据的不同逻辑，但从技术上讲，两个表在计数中应具有相同数量的CID。

在我的情况下，我确实在给定的时间段内有相同的计数，但我相信金额是不匹配的。

我想确定哪个CID有错误金额，并将此问题上报到第4级以查看业务逻辑。

有人可以告诉我如何找到不匹配的内容吗？

当我这样做时：

select count(CID) from Table A
union all 
select count(CID) from table B

我同时选择了1000。

Answer 1

一个快速的小例子......

create table tempA (CID int);
create table tempB (CID int);

insert into tempA values (1); 
insert into tempA values (2); 
insert into tempA values (2); 

insert into tempB values (1); 
insert into tempB values (2); 
insert into tempB values (3); 

mysql> select * from tempA;
+------+
| CID  |
+------+
|    1 |
|    2 |
|    2 |
+------+

mysql> select * from tempB;
+------+
| CID  |
+------+
|    1 |
|    2 |
|    3 |
+------+

select case when tempA_ct.CID is not null then tempA_ct.CID 
                                          else tempB_ct.CID end as CID, 

       case when a_CID_ct is null then 0 else a_CID_ct end as CID_A_count,

       case when b_CID_ct is null then 0 else b_CID_ct end as CID_B_count 

from   (select CID, count(CID) as a_CID_ct 
        from   tempA 
        group  by CID) as tempA_ct

        full outer join (
              select CID, count(CID) as b_CID_ct 
              from   tempB
              group  by CID) as tempB_ct
           on tempB_ct.CID=tempA_ct.CID 


CID     CID_A_COUNT     CID_B_COUNT
1       1               1
2       2               1
3       0               1
4       1               0

这也可以写成：

select CID,
       sum(case when tbln='A' then 1 else 0 end) as a_count, 
       sum(case when tbln='B' then 1 else 0 end) as b_count 
from   (select CID, 'A' as tbln 
        from tempA 
        union all 
        select CID, 'B' as tbln 
        from tempB) as joined
group  by CID        

+------+---------+---------+
| CID  | a_count | b_count |
+------+---------+---------+
|    1 |       1 |       1 |
|    2 |       2 |       1 |
|    3 |       0 |       1 |
|    4 |       1 |       0 |
+------+---------+---------+
4 rows in set (0.04 sec)

Answer 2

这是非常基础的，请稍后再阅读一些教程试试这个

如果您确定两个表中的记录数相同，则可以使用以下简单的sql。如果两个表中都有不同的CID，则需要使用左外连接和右外连接来查找它们。

select a.CID, a.amount 'TableA_amt', b.amount 'TableB_amt' 
from TableA A inner join TableB B 
ON a.CID=b.CID
Where a.amount <> b.amount

列中的数据不匹配

2 个答案: