Question

我想获得两个列表的交集：GameObject的列表和Realproperty的列表。并将此结果放入一个新列表中，该列表的类型为List＆lt;地段＆gt;。 Lot是GameObject的成员

class GameObject
{
    public string m_lotName;
    public Lot m_lot;
    //other members
}

class Lot
{
    public string m_lotName;
    //other members
}

class RealProperty
{
    public string m_name;
    //other members
}

List<GameObject> allLots = getAllLots();
List<RealProperty> soldRealProperties = getSoldRealProperties();

我想要一个 List＆lt; Lot＆gt; 将是以下结果：a List＆lt; GameObject＆gt; 由 List＆lt;过滤RealProperty＆gt; List＆lt;的每个游戏对象的位置GameObject＆gt; 我们测试 gameobject.m_lot.m_lotName 是否出现在 List＆lt; RealProperty＆gt;元素

似乎LINQ使其成为可能

我试过这样的事情：

List<Lot> soldLots = allLots
            .Select(a => a.GetComponent<Lot>().m_lotName)
            .Where(u => allLots
                       .Select(l => l.m_lot.m_lotName)
                       .Intersect(soldRealProperties
                           .Select(l2 => l2.m_name))
                           );

但是我遇到了很多错误，比如这些错误：

Type `string' does not contain a definition for `m_name' and no extension method `m_name' of type `string' could be found (are you missing a using directive or an assembly reference?)
Type `System.Collections.Generic.IEnumerable<string>' does not contain a member `Contains' and the best extension method overload `System.Linq.Queryable.Contains<object>(this System.Linq.IQueryable<object>, object)' has some invalid arguments
Extension method instance type `System.Collections.Generic.IEnumerable<string>' cannot be converted to `System.Linq.IQueryable<object>'

是否有一种简单的方法可以获得两个异构列表的交集？

Answer 1

您可以使用Enumerable.Join：

var intersecting = from game in allLots
                   join realProp in soldRealProperties
                   on game.m_lotName equals realProp.m_name
                   select game.m_lot;
List<Lot> soldLots = intersecting.ToList();

C＃中两个异构列表的交集

1 个答案: