Question

我是j2ee的新人。我已经阅读了一本j2ee书。有一个名为＆＃34; Soccer＆＃34;其中一个文件名＆＃34; list_league.view＆＃34;存在于＆＃34; /＆＃34;目录。这个应用程序使用MVC和一个Servlet文件，所以我的问题是如何创建这些扩展类型文件。

Web.xml文件的内容：

<servlet>
  <servlet-name>ListLeague</servlet-name>
  <servlet-class>s1314.view.ListLeagueServlet</servlet-class>
  </servlet>

  <servlet-mapping>
  <servlet-name>ListLeague</servlet-name>
  <servlet-class>list_league.view</servlet-class>
</servlet-mapping>

/index.html页面包含一个锚标记，引用＆＃34; list_leauge.view＆＃34;文件，下面：

<h3>Player</h3>
<ul><li><a href="list_league.view">List all league</a></li>
<li>Register for a league(TBA)</li>
</ul>

ListLeaugeServlet.java

import s1314.model.League;

@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
    throws ServletException, IOException {
processRequest(request, response);
//Creats the set of league
leagueList=new LinkedList();
leagueList.add(new League("2003","Spring","Soccer League(Spring`03)"));
leagueList.add(new League("2003","Summer","Summer Soccer Fest"));
leagueList.add(new League("2003","Fall","Fall Soccer League"));
leagueList.add(new League("2004","Spring","Summer Soccer Fest"));
leagueList.add(new League("2004","Summer","Soccer League(Spring`03)"));
leagueList.add(new League("2004","Fall","Fall Soccer League"));
}

Answer 1

您需要了解.view不是文件类型或扩展名。拦截对url的请求只是spring container模式。

您可以使用.view模式拦截应用程序的调度程序servlet。检查你的 dispatcher-servlet.xml了解视图解析程序下的视图文件夹

更新：

ListLeague servlet将被网址/list_league.view拦截。

Answer 2

在servlet映射中，您应该为servlet处理的URL指定模式。

<servlet-mapping>
  <servlet-name>ListLeague</servlet-name>
  <url-pattern>*.view</url-pattern>
</servlet-mapping>

url模式应该是路径或扩展名（其他不考虑此处）。一旦调用了servlet，它就应该返回一个视图，即一些JSP页面或另一个servlet。假设您有list_league.jsp：

<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<html>
<head>
  <title>List League</title>
</head>
<body>
  <c:forEach var="row" items="${leagueList}">
    Year: <c:out value="${row.year}"/><br>
    Season: <c:out value="${row.season}"/><br>
    League: <c:out value="${row.league}"/><br>
  </c:forEach>
</body>
</html>

servlet是一个转发到JSP以返回视图的控制器

@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
    throws ServletException, IOException {
processRequest(request, response);
  //Creats the set of league
  List<League> leagueList = new LinkedList<>();
  leagueList.add(new League("2003","Spring","Soccer League(Spring`03)"));
  leagueList.add(new League("2003","Summer","Summer Soccer Fest"));
  leagueList.add(new League("2003","Fall","Fall Soccer League"));
  leagueList.add(new League("2004","Spring","Summer Soccer Fest"));
  leagueList.add(new League("2004","Summer","Soccer League(Spring`03)"));
  leagueList.add(new League("2004","Fall","Fall Soccer League"));

  // forward a view with model
  request.setAttribute("leagueList", leagueList );
  request.getRequestDispatcher("list_league.jsp").forward(request, response); 
}

如何创建＆＃34; <filename> .view＆＃34; j2ee </filename>中的扩展文件

2 个答案: